Passing variable from a form via link but not submit!!

jonsof

Can i do that? i have the table below

echo "<table border=1 align=center><tr>
<td><table><tr><td><a href=links_submit.php?v1=".$v1."&v2=".$v2.">Sum</a></td></tr></table></td><td><table><tr><td>
<input type=text name=v1 size=5> <br>
<input type=text name=v2 size=5></td></tr>
</table></td></tr></table>";

I want each time i click on the link sum another table to be shown in the place of the previous form and add the v1 and v2.

Is this possible?

dotbob

<?
if($v1 || $v2)
{
?>

SHOW OTHER TABLE HERE

<?
}
else
{
?>

<table border=1 align=center>
<tr>
<td>
<table>
<tr>
<td>
<a href="javascript:document.tosubmit.submit();">Sum</a>
</td>
</tr>
</table>
</td>
<td>
<table>
<tr>
<td>
<form name="tosubmit" action="<?=$PHP_SELF?>" method="post">
<input type=text name=v1 size=5> <br>
<input type=text name=v2 size=5>
</form>
</td>
</tr>
</table>
</td>
</tr>
</table>
<?
}
?>

jonsof

I tested your code but when i press on the link the values from the fields are disappeared.

I want the result in the place of the input form, something like replacing

dotbob

<?
if($v1 || $v2)
{
echo $v1."<br>";
echo $v2."<br>";
}
else
{
?>

jonsof

neither that 🙁🙁

Is this work to your system?

eriksmoen

.
$_GET is the form method that allows you to do that. You cannot POST variables through links.

if(isset($_GET)){
//get information passed from link.
}

hope it helps.

jonsof

Then how would be look like the final script for this case?

rohithmr

<? 
if(isset($_POST['v1']) && isset($_POST['v2']))
{
echo $_POST['v1']."<br>";
echo $_POST['v2']."<br>";
} 
else 
{ 
?> 

<table border=1 align=center> 
<tr> 
<td> 
<table> 
<tr>
<td> 
<a href="javascript:document.tosubmit.submit();">Sum</a> 
</td> 
</tr> 
</table> 
</td> 
<td> 
<table> 
<tr> 
<td> 
<form name="tosubmit" action="<?echo $_SERVER['PHP_SELF'] ?>" method="post"> 
<input type=text name=v1 size=5> <br> 
<input type=text name=v2 size=5> 
</form> 
</td> 
</tr> 
</table> 
</td> 
</tr> 
</table> 
<? 
} 
?>

jonsof

🙁 it didn't work and the error message :

Forbidden
You don't have permission to access /java script:document.tosubmit.submit(); on this server.

Apache/1.3.27 Server at localhost Port 80

Why?

eriksmoen

try <a href="#" onClick="java...">

rohithmr

ohh thats cuz there shudd not be a space in 'javaScript'

So find this:

java script:document.tosubmit.submit();

and replace with:

javascript:document.tosubmit.submit();

That shudd work

jonsof

Nothing at all 🙁🙁
Does this work on your server?

rohithmr

yes....well when i put sum valu eon teh text box and click on th elink, it reloads the page and in place of the table i see the 2 values i entered b4.

jonsof

When you broswe via localhost?

cschotch

i just tried this and it givs the 2 values in the browser in place of the table....And I do it on my local computer with apache on LOCALHOST

<? 
if(isset($_POST['v1']) && isset($_POST['v2']))
{
echo $_POST['v1']."<br>";
echo $_POST['v2']."<br>";
} 
else 
{ 
?> 

<table border=1 align=center> 
<tr> 
<td> 
<table> 
<tr>
<td> 
<a href="javascript:document.tosubmit.submit();">Sum</a> 
</td> 
</tr> 
</table> 
</td> 
<td> 
<table> 
<tr> 
<td> 
<form name="tosubmit" action="<?echo $_SERVER['PHP_SELF'] ?>" method="post"> 
<input type=text name=v1 size=5> <br> 
<input type=text name=v2 size=5> 
</form> 
</td> 
</tr> 
</table> 
</td> 
</tr> 
</table> 
<? 
} 
?>

Now it does go to a different screen with the values but did you want them added up and the value of the 2 shown?

dotbob

I don't know what all the fuss is about.

The original answer (my second post) works just fine locally, and on a live testbed.

<?
if($fussy_sod == "rohithmir")
{
echo "Apologies for using deprecated syntax and not posting my answer in pretty highlighted text";
}
?>

I've used a variation of this code a thousand times before.

Jonsof, it seems that you are either implementing this code incorrectly within your pages or you have a problem with your local dev setup.

cschotch

Then theres something wrong with mine too because I tried it and it doesnt ever print out the values or anything it just stays on the 1 form portion.....

jonsof

Dear dotbob your code of that you posted previously didn't work unless at the pont you say SHOW OTHER TABLE HERE somenone must put some html code.

I don't know why the your code doesn't work though i cut and paste into my IDE and then run the php under the localhost 🙁

dotbob

give me strength!!

NO S##T SHERLOCK!!??

It was an example man.

ARGH!!!!!!!

dotbob

right. ok then, how about replacing the reference to

$_SERVER['PHP_SELF']

with a relative link to your page.

i.e. If you're script is named formpost.php...

<? 
if(isset($_POST['v1']) && isset($_POST['v2']))
{
echo $_POST['v1']."<br>";
echo $_POST['v2']."<br>";
} 
else 
{ 
?> 

<table border=1 align=center> 
<tr> 
<td> 
<table> 
<tr>
<td> 
<a href="javascript:document.tosubmit.submit();">Sum</a> 
</td> 
</tr> 
</table> 
</td> 
<td> 
<table> 
<tr> 
<td> 
<form name="tosubmit" action="formpost.php" method="post"> 
<input type=text name=v1 size=5> <br> 
<input type=text name=v2 size=5> 
</form> 
</td> 
</tr> 
</table> 
</td> 
</tr> 
</table> 
<? 
} 
?>

And if that doesn't work then you're on your own 'cause it works here. Anyone who doubts me, I'll send you the screenshots.