preg_grep

wil

I am having trouble with getting the values I want returned. Please help if you can. This is the first time I have done anythiing with regex.

<?php
$filename = "c:\\program files\\apache group\\apache\\htdocs\\regex.txt";
$fd = fopen($filename, "r");
$fstring = fread($fd, filesize($filename));
fclose($fd);
$line = explode("\n", $fstring);

$array = preg_grep('/\\d\\d/', $line);

foreach ($array as  $get)
{
	print ("$get<br>");
}
?>

regex.txt:

11 theew
12 the56
13 wer12
14 wer5

Values I get returned:

11 theew
12 the56
13 wer12
14 wer5

Values I want:

11
12
13
14

Thanks in advance,
Wil

diego25

Instead of
$array = preg_grep('/\d\d/', $line);
try
preg_match_all('/^(\d\d)/', $line, $array);

Then convert your foreach loop to a for loop starting at 1. Read the PHP manual on preg_match_all.

Diego

wil

I tried what you said and I get:

Notice: Array to string conversion in c:\program files\apache group\apache\htdocs\strip3.php on line 8
Array

Here is the code I used:

<?php
$filename = "c:\\program files\\apache group\\apache\\htdocs\\regex.txt";
$fd = fopen($filename, "r");
$fstring = fread($fd, filesize($filename));
fclose($fd);
$line = explode("\n", $fstring);

preg_match_all('/^(\\d\\d)/',$line, $output);

$c = count($output);

If ($c>0) {
for( $i=1; $i<$c ; $i++) {
print ( "$output<br>");
}
} else {

print ("No Good");
}

?>

diego25

$output is an array, so you can't just print it inside a string...i think you want

print $output[$i];

Diego

wil

I had forgotten to add the $i. Even changed it still gives me the same error message.

FYI line 8 is

preg_match_all('/^{(\d\d)/',$line,} $output);

Weedpacket

$line is an array, you want it to be a string.

Don't use explode() it on $n (you'd be working on $fstring instead of $line), and tack "m" on to the end of the regexp:

/^(\d\d)/m