read from array instead of file

[vocoder]

i have an xml file stored in an array (after getting it via nusoap)

so basically i have it stored in $result. If i do a print_r($result), it prints out the correct xml file.

Now, I have the code

$file = "myfile.xml";
// open XML file
if (!($fp = fopen($file, "r")))
{
    die("Cannot locate XML data file: $file");
}

// read and parse data
while ($data = fread($fp, 4096))
{
    // error handler
	if (!xml_parse($xml_parser, $data, feof($fp)))
	{
    die(sprintf("XML error: %s at line %d",
xml_error_string(xml_get_error_code($xml_parser)),
xml_get_current_line_number($xml_parser)));
    }
}

this is for opening up an xml file....i had saved that xml file to a file..but i don't want to do that anymore, i want to do the same thing as above, but instead of reading from a file, i need to read it from $result. How do i do this?

[philipolson]

Consider this minor rewrite:

$file = "myfile.xml";

if (!is_readable($file)) {
    print "Could not read file ($file), exiting";
    exit;
}

$lines = file($file);

foreach ($lines as $line) {
    if (!xml_parse($xml_parser, $data, $line)) {
        print "blah";
    }
}

It should be clearer now as file() simply puts the contents of a file in an array. You can implement various other error handling mechanisms too, such as count..