PHP with an HTML Form Question

Ahriman

I have a question about the checkbox in a form...for example would this code work.

."<input name="checkbox" type="checkbox" value="checkbox">";
if($checkbox == checked) {
				echo "<input type=\"file\" name=\"NULL\"><br><br>";
			} else {
				echo "<input type=\"file\" name=\"miconfname\"><br><br>";
			}

very new to PHP I know this is probally a dumb question...but please help me out.

cgraz

if($checkbox == checked)

$checkbox would never equal checked--the value you set for it was checkbox. If you wanted it to equal checked, you would have to change the value in your form to

Which is why your if statement wouldn't work the way you want it to. It would always

echo "<input type=\"file\" name=\"miconfname\"><br><br>";

What exactly are you trying to do?

Your code would also produce a parse error

."<input name="checkbox" type="checkbox" value="checkbox">";

The entire input tag is within double quotes, but then you have double quotes within that. You can't have double quotes within doublequotes. Also, you have a period right before the opening quote, so I'm assuming you're concatenating (adding onto) by using the <input> tag. To get those quotes within quotes to work, you either need to escape them () or use single quotes.

echo "<input name=\"checkbox\" type=\"checkbox\" value=\"checked\">";

// or

echo "<input name='checkbox' type='checkbox' value='checked'>";

Cgraz

scbmx

<?php
echo "<input name=\"checkbox\" type=\"checkbox\" value=\"yourvalue\">";
if($checkbox == 'yourvalue') {
                echo "<input type=\"file\" name=\"NULL\"><br><br>";
            } else {
                echo "<input type=\"file\" name=\"miconfname\"><br><br>";
            }
?>

that should work

Ahriman

sorry about that the ."<input>...."; was part of an echo.
echo "blah blah blah"
."<input>"; I actually think I got it figured out using

."<input type=\"checkbox\" name=\"changefile\" value=\"1\" checked><br>"
			."<input type=\"file\" name=\"miconfname\"><br><br>"

Then in the function it calls I have

if ($changefile == 1) { $miconfname = NULL; }

Thanks for your help once again This PHP has been driving me crazy trying to learn it. First time I have ever done any kind of programming really. without these forums I would still be lost.