enter key not working as submit method

[beckstei]

A simple form, one text field that submits to $PHP_SELF works fine when the submit key is clicked, but does not work
when the enter key is hit.

I'm using the following form:

<form action="<? $PHP_SELF ?>" method="post">
<input name="name" size="30">
<input type="submit" name="submit" value="submit">
</form>

script is invoked with

if($submit){
then do stuff
}

When the enter key is hit the if statement is not invoked.

If anyone can explain, I'd appreciate it.

Thanks
B

[xblue]

Hi B,

I'm not absolutely sure if all browsers behave the same concerning this, but I've seen the following behaviour (I think with IE):

If you click the button, the button's name and value is submitted together with the other form data, but if you submit the form via enter key, the button's name and value is skipped.

You could try to tell whether something has been submitted by checking for that "name" input field, or define an additional hidden form field to see if this solves the problem.

Hope this helps...

[apepelis]

xblue is correct.
I have this same exampe problem with IE.
Also, I had multiple forms per page.

[mahendrakalkura]

i use ie6

and enter key works just fine

[s2e]

I have several php forms that submit correctly using the enter key and several that don't. If this is a browser issue why do some work and some not. Any solution to make them all work using the Enter Key, particularly single value search query?

Sample Search Form and Handle Query (Enter Key does not submit correctly but form works on click or tab to submit and enter):

Form Page
<form action="handle.php" method="post" name="form" id="form">
<input name="pop_rate_id" type="text" id="pop_rate_id" size="15" />
<input name="pop_rate" type="submit" value="Submit" id="pop_rate"/>
</form>

Handle Page
<?php if (isset($POST['pop_rate'])) {
if(empty($POST['pop_rate_id'])) {
$id = FALSE;
$message = '<p>Please go back and enter a Load ID.</p>';
} else {
$id = $POST['pop_rate_id'];
}
if($id) {
require_once('./mysql_connect.php');
$query = "SELECT value FROM table WHERE value = '$id'";
$result = @($query);
$row = @mysql_fetch_array($result, MYSQL_NUM);
if ($row) {
echo $row[0];
} else {
}
}
if(isset($POST['var'])) echo $_POST['var'];
}
?>