Adding descriptions to photo gallery

[kilbey1]

I've got very simple code that functions as a slide show when a user hits a button:

<? if (!isset($photo)) $photo = 1; ?>
              <img src="photogallery\<?=$photo?>.jpg"></td>
<? $newphoto = ($photo + 1);?>

What must I do to also put some text description below the corresponding image as it changes?

Thanks,
Eve

[amcgrath]

Well, there are a lot of different options for you, I'll assume you do not store the information in a database, so doing something like putting the descriptions in an array (key would be the photo nubmer, value would be the description) and output that way,

ex:
<img src=<?= $photo_info[$num] ?>.jpg><br>$photo_info[$descr]

[kilbey1]

Is this anywhere close to where I need to be? Btw, I get a parse error at line

echo '<img src="';

<?if (!isset($photo)) {
		$photo = 1;
		$num = array('1', '2', '3');
		$descr = array('1' => 'Test Desc','2' => 'Test Desc 2','3' => 'Test Desc 3');
		$photo_info = 'photogallery\';
		echo '<img src="';
		echo .= $photo_info[$photo];
		echo .= '.jpg"><br>';
		echo .= $photo_info[$descr];
		echo .= '</td>';
//		$newphoto = ($photo + 1);
		}
?>

[amcgrath]

try something like this instead:

<?

if (!isset($photo)) {
$photo = 1;
$photo_info = array('1' => 'Test Desc',
'2' => 'Test Desc 2',
'3' => 'Test Desc 3');
echo '<img src="/path/image_' . $photo . '.jpg>' .
'<br>' . $photo_info[$photo] ;

    $newphoto = ($photo + 1);
    }

?>

That should work, but are you trying to time it so it automatically changes or something? And, if you are passing $photo on a user click, then you'll wanna rework the first two lines.

lemme know if it helps.

amc

[kilbey1]

Thanks, that did help. You're right, I'm having a user click 'next photo' to advance to the next in the array. Your code works fine; the code I'm trying to wrap around the 'next photo' button does not.

<?
if ($photo !=15) {
		$newphoto = ($photo + 1); 
        echo '<input type="button" value="Next photo" onClick="javascript:location.href=';
		echo .= 'index.php?photo=';
		echo .= $newphoto;
		echo .= '" name="button2">';
          }
else {
		echo '<input type="button" value="View Slideshow Again" onClick="index.php">";
	}
?>

What am I doing wrong? It's also giving me a parse error at this line:
echo .= 'index.php\?photo=';

• Eve

[amcgrath]

Try this:

<?php
if ($photo < 15) {
$newphoto = ($photo + 1);
echo '<input type="button" ' .
'value="Next photo" ' .
'onClick="java script:location.href=' .
'index.php?photo=' .
$newphoto .
'" name="button2">';
} else {
echo '<input type="button" value="View Slideshow Again" onClick="index.php">
';
}
?>

amc

[kilbey1]

Almost! A few changes and the code looks like this (javascript required ' '):

<?php 
	if ($photo < 15) { 
		$newphoto = ($photo + 1); 
		echo '<input type="button" ' . 
		'value="Next photo" ' . 
		'onClick="javascript:location.href=' . 
		'\'index.php?photo=' . 
		$newphoto . '.jpg\'" name="button2">'; 
} else { 
echo '<input type="button" value="Return to Start" onClick="index.php"> 
'; 
} 
?>

According to view source, the counter is working. However, no image shows up when switching to a new photo.

Does this have something to do with my isset code in the first half?

<? 

if (!isset($photo)) { 
$photo = 1; 
$photo_info = array('1' => 'Test Desc', 
'2' => 'Desc 2', 
'3' => 'Desc 3',
'4' => 'Desc 4',
'5' => 'Desc 5',
'6' => 'Desc 6',
'7' => 'Desc 7',
'8' => 'Desc 8',
'9' => 'Desc 9',
'10' => 'Desc 10',
'11' => 'Desc 11',
'12' => 'Desc 12',
'13' => 'Desc 13',
'14' => 'Desc 14',
'15' => 'Desc 15',); 
echo '<img src="photogallery\\' . $photo . '.jpg">' . 
'<br>' . $photo_info[$photo] ; 

} 

?> 

• Eve

[amcgrath]

Not seeing the entire script, yea your isset() is prolly causing problems. CHange it to this:

<?

if (!isset($photo)) {
$photo = 1;
}

$photo_info = array('1' => 'Test Desc',
'2' => 'Desc 2',
'3' => 'Desc 3',
'4' => 'Desc 4',
'5' => 'Desc 5',
'6' => 'Desc 6',
'7' => 'Desc 7',
'8' => 'Desc 8',
'9' => 'Desc 9',
'10' => 'Desc 10',
'11' => 'Desc 11',
'12' => 'Desc 12',
'13' => 'Desc 13',
'14' => 'Desc 14',
'15' => 'Desc 15',);
echo '<img src="photogallery' . $photo . '.jpg">' .
'<br>' . $photo_info[$photo] ;

?>

amc

[kilbey1]

Thanks, that did it! It's working great; problem solved!

• Eve