php form popup

Vinnepin

Hey guys,

Does anybody here knows this :

I have created a form like this :

</form>

Now i want this, when the form is submitted i want to open a popup window. So that this page is still the same.

But this is the tricky one. I want the popup to be a php file. And the select value to be stored in an variable like this :
$rating = $_POST['rating'];

I have tried this with a javascript popup but i couldn't get the form value's 🙁

Do u guys know how to do this?

Vinnie

cgraz

Worked for me. Here's the code i used.

-- form.php --

<html>

<head>

<SCRIPT TYPE="text/javascript">
<!--
function popupform(myform, windowname)
{
if (! window.focus)return true;
window.open('', windowname, 'height=200,width=400,scrollbars=yes');
myform.target=windowname;
return true;
}
//-->
</SCRIPT>


</head>

<body>

<form name="rating" method="post" action="popup.php" onSubmit="popupform(this, 'join')"> 

<select name="rating"> 
<option value="5.0" selected>5</option> 
<option value="4.0">4</option> 
<option value="3.0">3</option> 
<option value="2.0">2</option> 
<option value="1.0">1</option> 
<option value="0.0">0</option> 
</select> 
<input type="hidden" name="events" value="rating"> 
<input type="submit" value="Go!"> 

</form> 

</body>

</html>

-- end of form.php --

-- popup.php --

<?

echo $_POST['rating'];

?>

-- end of popup.php --

I selected 5, clicked go, and it echo'd 5.0

If that still doesn't work for you, then for popup.php, you should also try

echo $rating; (if register globals is on)

and

echo $_HTTP_POST_VARS['rating']; (for versions earlier than 4.1.0)

Cgraz