Uploaded file's extension

[nca]

How can I have php find out what the uploaded file's extension is?

[cgraz]

Use strrchr()

If your form is input type file with a name of userfile:

<?

$userfile = $_FILES['userfile']['name'];

   $extension = strrchr($userfile, ".");
   echo "Extension: " . $extension . "<br>\n";

?>

Cgraz

[nca]

Thanks for the reply.

Could you tell me how to have that code find out if the extension is jpg, gif, or bmp and if it is not one of the 3, then say that it is an invalid upload?

Thanks!

[cgraz]

ahh, why didn't you say that earlier! lol

I thought you wanted the file extension for something other than that. To do that, check the file type.

if ($_FILES['userfile']['type'] != (image/pjpeg) || (image/gif) || (image/bmp)) {
   echo "Invalid Upload";
} else {
   echo "Valid Upload";
   // process upload here
}

I'm not sure on the mime type on bmp's, i just guessed. It seems logical that a bmp would be image/bmp.

Anwyays that code should work. Make sure to change userfile to the name you gave the file input on your form.

Cgraz

EDIT: also, have a look around here: http://www.php.net/manual/en/features.file-upload.php#features.file-upload.post-method

[diego25]

Are you sure you can do this?

if ($_FILES['userfile']['type'] != (image/pjpeg) || (image/gif) || (image/bmp)) {

Despite the fact that quots are missing, I don't think you can use the OR operator that way....

Diego

[cgraz]

whoops! 😉 I gotta start paying more attention:

<?

echo "FILE TYPE: " . $_FILES['userfile']['type'] . "<br>\n";

if (($_FILES['userfile']['type'] != ('image/pjpeg')) && ($_FILES['userfile']['type'] != ('image/gif')) && ($_FILES['userfile']['type'] != ('image/bmp'))) {
   echo "invalid file";
} else {
   echo "valid file";
}

?> 

Thanks for catching that Diego.

Cgraz

[orangehairedboy]

The official MIME type for a .bmp file is image/x-xbitmap...although many browsers support image/bmp.

If you want to be sure, check for both...but I must point out that BMP files are not acceptable image formats for display in a web page...just in case that's what your script is looking for 🆒!

OHB

[Weedpacket]

Originally posted by orangehairedboy
...but I must point out that BMP files are not acceptable image formats for display in a web page...just in case that's what your script is looking for!

And if that is what your script is looking for, then PNG files are an acceptable format 🆒!

The [man]GetImageSize[/man] function will identify (more reliably than looking at file extension or MIME type) whether an image is GIF, JPEG, PNG, BMP and maybe others depending on PHP version.

[orangehairedboy]

And if you want to use PNG files, the MIME type is image/png! 🙂

[nca]

if (is_uploaded_file($fobject)){
if (($_FILES['fobject']['type'] != ('image/jpeg')) && ($_FILES['fobject']['type'] != ('image/jpg')) && ($_FILES['fobject']['type'] != ('image/gif')) && ($_FILES['fobject']['type'] != ('image/x-xbitmap'))) {
   echo "Invalid file type. Only acceptable file types are jpeg, jpg, gif, and bmp.";
   exit;
}
}

Every time I upload it says it is not a vaild file type. The form input for the upload is this...

<form name="myform" enctype="multipart/form-data" method="post" action="script.php">
<input type="file" name="fobject" size="55"></b><br><br>
<input name="go" type="submit" value="UPLOAD">

I don't have to change "type" to anything, right???

[diego25]

Try printing out $_FILES['fobject']['type'], and see what you get...

Diego

[nca]

It says...

Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING

Here is what I put at the top of the script...

if (is_uploaded_file($fobject)){
echo "$_FILES['fobject']['type']";
exit;
}

[orangehairedboy]

Originally posted by nca
It says...

Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING

Here is what I put at the top of the script...

if (is_uploaded_file($fobject)){
echo "$_FILES['fobject']['type']";
exit;
}

[/B]

Something to remember is that $_FILES['fobject']['type'] will only return a MIME type if it was specified by the browser. You might also want to look at $_FILES['fobject']['name'] to see what the extension on the file is.

Also, I believe your IF statement should be:

if ( is_uploaded_file( $_FILES['fobject']['tmp_name'] ) ) {

OHB

[nca]

Ok, here is what I am using now, and it still does not work...

if (is_uploaded_file($fobject)){
if (($_FILES['fobject']['name'] != ('image/jpeg')) && ($_FILES['fobject']['name'] != ('image/jpg')) && ($_FILES['fobject']['name'] != ('image/gif')) && ($_FILES['fobject']['name'] != ('image/x-xbitmap'))) {
   echo "Invalid file type. Only acceptable file types are jpeg, jpg, gif, and bmp.";
   exit;
}
}

Weedpacket thought I should use GetImageSize, how would I use that??

[diego25]

echo "$_FILES['fobject']['type']";

Why use quotes when you don't need them? Try
echo $_FILES['fobject']['type'];

if (is_uploaded_file($fobject)){

if (($_FILES['fobject']['name']

Why use code that assumes register_globals to be on and then off? i.e. why are you using $fobject if you're using $_FILES['fobject'] later? Keep your code consistent.

Weedpacket thought I should use GetImageSize, how would I use that??

This is taken straight from the documentation at http://www.php.net/manual/en/function.getimagesize.php:

[getimagesize()] Returns an array with 4 elements. Index 0 contains the width of the image in pixels. Index 1 contains the height. Index 2 is a flag indicating the type of the image: 1 = GIF, 2 = JPG, 3 = PNG, 4 = SWF, 5 = PSD, 6 = BMP, 7 = TIFF(intel byte order), 8 = TIFF(motorola byte order), 9 = JPC, 10 = JP2, 11 = JPX, 12 = JB2, 13 = SWC, 14 = IFF.

Diego

[nca]

I have it working now. Thanks everybody for all your help! 😃