Simple if - else question - But tricky enough

[mahendrakalkura]

have a small dought

if have a thing like this

if(condition1) {

    if(condition2) {

            if(condition3) {

            }

    }

} else {

}

i want it this way

if the condition in any of the if fails - ie: condition 1 or condition 2 or condition 3 then i want the control to go to else

if cant do this

if(condition1 || condition2 || condition3) {

} else {

}

is there any other way

thanks for seeing it

[rohithmr]

if (condition1 && condition2 && condition3) {
//All 3 condition are true

} else {
//One or more of the conditions evaluated false.
}

[mahendrakalkura]

this is my script

$username = $_POST["username"];

$password = $_POST["password"];

if(isset($Submit)) {

$result = mysql_query("SELECT password , id FROM members WHERE username = '$username'",$connect_parameters);

$count = mysql_num_rows($result);

$row = mysql_fetch_row($result);

if($count == 1) {

    if($password == $row[0]) {

        $access = 1;

        echo "Thank You for Logging In";

    } 

}

}  else {

//  show login form again    

}

so i cant do

if(condition1 && condition2 && condition3) {

} else {

}

because i can know the condition2 only if i get inside condition1 if block and so on

thanks

[Weedpacket]

Well then you're stuck on the gap between $condition1 and $condition2, but there's nothing stopping you from merging $condition2 and $condition3 together.

[mahendrakalkura]

hey weedpacket

i know that you are the one person who always has an answer to everything

please help me on this

even if i merge 2 and 3 what about 1

help me

[orangehairedboy]

It would become:

$username = $_POST["username"];
$password = $_POST["password"];
if(isset($Submit)) {
    $result = mysql_query("SELECT password , id FROM members WHERE username = '$username'",$connect_parameters);
    $count = mysql_num_rows($result);
    $row = mysql_fetch_row($result);
    if ( ($count == 1) && ($password == $row[0]) ) {
         $access = 1;
         echo "Thank You for Logging In";
    }
}  else {
    //  show login form again    

}

You can't further merge with condition 1 because of the extra code in between. Well that's a lie...you technically could...but you would have UGLY code...this is the most you should do.

[mahendrakalkura]

hey orangehairedboy

just see the code

if the form is submitted and the password is wrong where will the control end up

it wont show the form again

so think some solution for it please

[ahundiak]

$access = 0;
if(isset($Submit)) {

  $result = mysql_query("SELECT password , id FROM members WHERE username = '$username'",$connect_parameters);

  $count = mysql_num_rows($result);

  $row = mysql_fetch_row($result);

  if($count == 1) {

if($password == $row[0]) {

  $access = 1;

  echo "Thank You for Logging In";

}                           
  }
}  

if ($access == 0) {

  //  show login form again    

}

[mahendrakalkura]

thanks ahundiak

thats the best solution i could ever get

thanks

[sijis]

question;
why don't you check the username and password match during the sql query?

try merging it this way:

$access = 0;
if(isset($Submit)) {

  $result = mysql_query("SELECT password , username FROM members WHERE username = '$username' AND password = '$password'",$connect_parameters);

  $count = mysql_num_rows($result);

  if($count == 1) {

  $access = 1;
        // set cookies, session vars... etc..
  echo "Thank You for Logging In";
  }
}  

if ($access == 0) {

  //  show login form again    

}