Function expression problem

[Sonic_Rage]

Here is some code I have and there is something I'm not quite doing right, the function is giving me a problem when I try to verify if a field is NULL. The comment section shows the problem...

function display_wallpaper($wallpaper_array)
{
open_table_main();

  if (!is_array($wallpaper_array))  //display all wallpaper in the array passed in
  {
     echo "<P> &#149; No wallpaper currently available in this category<br>";
  }
  else
  {
    echo "<table width = \"100%\" border = 0>";

// Make each row contain 3 or more images

$i=0;
foreach ($wallpaper_array as $row)
  {
    { 
      if (!($i % 3))
        { 
           echo"<tr>";
        }
       $i++;
     }
  echo"<TD>";
  echo "<Table Border=0 Width=150 Cellpadding=0 Cellspacing=0>\n";
  echo "<TR><TD COLSPAN=2><IMG SRC=\"downloads/wallpaper/".$row["thumb_img"]."\" Border=0></TD></TR>\n";

  echo "<TR><TD><P CLASS=link>";
  $url = "show_wallpaper.php?wallpaperid=".($row["wallpaperid"]);
  $title =  $row["dims_01"];
  do_html_url($url, $title);
  echo"</TD><TD><P CLASS=small>".$row["size_01"]."</TD></TR>\n";
  echo "<TR><TD colspan=2><P CLASS=small>Viewed: ".$row["downloads"]." times</TD></TR>\n";

// Here is the actual problem, I want this to NOT display any of the following info if it finds these empty. But it keeps giving me a function error. 
// What am I doing wrong here?

if ($wallpaper_array[dims_02] == NOT NULL) 
{
      echo "<TR><TD><P CLASS=link>";
      $url2 = "show_wallpaper_1024.php?wallpaperid=".($row["wallpaperid"]);
      $title2 =  $row["dims_02"];
      do_html_url($url2, $title2);
      echo"</TD><TD><P class=small>".$row["size_02"]."</TD></TR>\n";
      echo "<TR><TD colspan=2><P class=small>Viewed: ".$row["downloads_02"]." times</TD></TR>\n";
}
else
{
      echo "<TR><TD colspan=2><P class=small>&nbsp;</TD></TR>\n";
}

// End Problem Area

  echo "</Table></TD>";
  }
echo "</tr>";
echo"</table>";
  }
close_table_main();
}

Any suggestions on what I'm doing is wrong is greatly appreciated. I'm sure it has to do with this part here:

if ($wallpaper_array[dims_02] == NOT NULL) // Help! 
{
      echo "<TR><TD><P CLASS=link>";
      $url2 = "show_wallpaper_1024.php?wallpaperid=".($row["wallpaperid"]);
      $title2 =  $row["dims_02"];
      do_html_url($url2, $title2);
      echo"</TD><TD><P class=small>".$row["size_02"]."</TD></TR>\n";
      echo "<TR><TD colspan=2><P class=small>Viewed: ".$row["downloads_02"]." times</TD></TR>\n";
}

[diego25]

if ($wallpaper_array[dims_02] == NOT NULL)

There are many syntax errors there. First of all, what is dims_02? If it's a constant, it should be, by convention, all capitals, i.e. DIMS_02. If it's a variable, you're missing the '$'. And what's "NOT"? It doesn't exist in PHP. Use the != operator instead.

Diego

[Sonic_Rage]

Dims_02 is actually a field in the database. Basically if that field has no value, I do not want those other lines to appear.

I did try using != NULL instead but that didn't work either.

[diego25]

Dims_02 is actually a field in the database

Then there should be quotes around it.

Basically if that field has no value, I do not want those other lines to appear.

That maybe because the default value of your field is an empty string. Try

if ($wallpaper_array['dims_02'] != '')

Diego

[Sonic_Rage]

Thank you, that info helped me figure it out, after I changed it and it still didn't work I figured out why, I needed to replace the $wallpaper_array with actually $row and then it worked.

Instead of this:

if ($wallpaper_array['dims_02'] != '')

I changed it to this:

if ($row['dims_02'] != '') // Now this works like I need it to.
{
      $url2 = "show_wallpaper_1024.php?wallpaperid=".($row["wallpaperid"]);
      echo "<TR><TD><P CLASS=link>";
      $title2 =  $row["dims_02"];
      do_html_url($url2, $title2);
      echo"</TD><TD><P class=small>".$row["size_02"]."</TD></TR>\n";
      echo "<TR><TD colspan=2><P class=small>Viewed: ".$row["downloads_02"]." times</TD></TR>\n";
}

Thank you for your help Diego 😃