Back a directory

ptbsG_Man

Hi i am looking for a way to go back a directory i was doing a function with
function go_back ($path_full) {
$in = strrev($path_full);
$inpos($in, "/");
return $inpos;
}

and calling it form <a href="?<?= go_back() ?>">back</a>

cgraz

You mean just a link that goes back to the last page you were at? Try

I think you can even go back two or three or more with

and so forth.

Cgraz

ptbsG_Man

no it is for directorys i need it to change
/home/wwwroot/user/dir/dir2
to
/home/wwwroot/user/dir

diego25

function go_back ($path_full) {
$in = strrev($path_full);
$inpos($in, "/");
return $inpos;
}

and calling it form <a href="?<?= go_back() ?>">back</a>

Why are you calling with go_back()? Your function definition explicitly says that it requires a variable $path_full to be passed to it.

Also, $inpos() is not a function, so $inpos($in, "/"); doesn't make sense. And then, return $inpos; isn't defined...

Diego

ptbsG_Man

opps that was to be $inpos = strpos($in, "/");
and i thought that having the $path_full in the function would be the default var. if i do not supply one????

diego25

But you didn't give it a default value. To give a default value, you do something like this:

function go_back ($path_full = "") {

Diego

juschillinnow

I didn't read the whole post, but cant you break up everything by the / or the \ and then take the last string and take it off?

That would make sense to me to go back a directory

ptbsG_Man

but $path_full already has a value and that would be the current dir. IE.. /home/wwwroot/user/dir/dir2
if you look @ the script i included you might make more sence of what it dose

diego25

Even though they have the same name, they are different variables because they are in different variable scopes.

Diego

ptbsG_Man

Crap thats right (im in the functions chapter of my o'reilly book) im going to try that also dose my function look like it will work? ...... hmm how would i make $path_full in the funcion be what it is outsie the function ? is it ....($path_full = $_GLOBALS[$path_full]

diego25

Just pass it to the function:

<?= go_back($path_full) ?>

Diego

ptbsG_Man

hmm well it kinda works when i run the script it comes out with 8 so that wont work also in doing some debuging i had it output just the reversed string nd that works to a point when i change directorys to one with a space say new floder it only outputs "redlof" and not "wen redlof" any ideas on how to resolve this

Thanks for putting up with me

suntra

Maybe this can help...

<?
 function go_back($path) {
  $script = $path;
  $pos_last_slash = strrpos($script, "/");
  $directory = substr($script, 0, $pos_last_slash);
  $pos_2_last_slash = strrpos($directory, "/");
  $back_directory = substr($script, 0, $pos_2_last_slash) . "/";
  return $back_directory;
 }
?>

This was originally made if you set $path egual to $_SERVER["SCRIPT_NAME"].

ptbsG_Man

cool that works better but still has the problem with spaces and am thinking i shoud add a

eregi(" ", $path_full)

but will that work or should the PHP thing for space witch i cant find

also it goes back 2 diectories ie /home/testsize/test turns into /home

ive got to get to work
Thanks

altexis

just poke a little the code above... use this:

<?
 function go_back($path) {
  return substr($path, 0, strrpos($path, "/"));
 }
?>

this would work provided that the $path does NOT end with a slash, and that you use if for a 2nd or more level directory
ie. it would give an error if $path is "/home"

ptbsG_Man

ok your all going to hate my 🙁 the last script works but i gave you guys the wrong info. this is how the scrip works

there is
$path = "/home";
$path_name = $SESSION["user"];
$path_folder = $REQUEST['path_folder'];
then
$path_full puts them together like so

$path/$path_name$path_folder

an exapmle woul be like this

$path = /home //root folder
$path_name = testsize //there username
$path_folder = /test // ther first folder

now $path_folder is not required and if is not given then there root dir is shown and it builds up from there what i need is a way to do what the last post did only with the $path_folder and have it equal nothing when it get's to the end so...

$path_folder = /test/1/342/124
BACK
$path_folder = /test/1/342
BACK
$path_folder = /test/1
BACK
$path_folder = /test
BACK
$path_folder =

keep inmind that there is no ending / like $path_full did

and once again sorry for being so stubern with this post and thanks