mktime

legal-medium

If $x is larger than "33" the $date variable always returns "1969-12-31" , why is this?

//Example Change the variable to any number less than 34 and it works
//Change the $x variable to any number more than 34 and always returns "1969-12-31"

$x=35;

//Returns some unix date stamp I think
$calculate= mktime(0,0,0, date('m') ,date('d'), date('Y')-$x);

//Returns variable in date(8) data type format to be used in SQL query
echo $date = date('Y-m-d', $calculate);

volleytotal_ch

can't work because the Unix Epoc starts at 1.1.1970!

[mktime] Returns the Unix timestamp corresponding to the arguments given. This timestamp is a long integer containing the number of seconds between the Unix Epoch (January 1 1970) and the time specified.

legal-medium

So what should I do? Is there another function?

Thanks in advance

volleytotal_ch

what do you want to do?

legal-medium

What do you think, I want to do. I want to subtract $x fom $calculate, and return date(8) data type varialble.

volleytotal_ch

just a winNT problem 🙂

mktime works under Win NT not for negative values.

junior member ....

legal-medium

I dont use Win NT, do you understand english?

keith73

Originally posted by legal-medium
I dont use Win NT, do you understand english?

In case you don't read well, you'll see volley is from Switzerland. So english IS his/her second language.

And you have to learn to RELAX. People are trying to help you and you're getting very confrontational. Read the manual at http://www.php.net. If you don't find your answer there, do a search on these forums FIRST before posting the question. 9 times out of 10 the quesiton has been answered before.

as to the answer to your dilemna, try writing your own function. Don't use mktime. Each year has 31536000 seconds in it. multiply that by the # of years and then do your math.

seconds in a year

365 24 60 * 60 = 31536000

do your math, then reverse the formula.

keith