getting only directies using file system functions

abbireddy

Hi all,

I am developing a treeview for PHP. I need to show only directories available in a selcted directory. I don't want to read whole directory and check file, directory. becouse 1000's of files exists in the directory.
is there any way we can read only the directories ..

best regards
venkat.

cahva

Try this:

<?php
$dirtree=$_SERVER['DOCUMENT_ROOT'].'/somedir';
if ($dir = @opendir($dirtree)) {
	while (($file = readdir($dir)) !== false) {
		if (is_dir($file)) {
              echo $file."<br />";
           }

}
closedir($dir);
}
?>

abbireddy

Hi,

thank you,

Actually this will read whole directory contents and display if that is a directory.
I don't want to scan whole directory contents , I want to get in a directory on directories.

e.g : consider venkat is a directory in that I have 500 files , 501 is the directory. in this case I need to skip all 500 loops and print 501 becos it is directory. I dont want to waste those all 500 loops I want to skip directly to 501 loop ..how?

Please help me in this regard.

venkat.

cahva

I really dont know what is the problem with the loop. You HAVE to loop through the directory to find the dirs using is_dir().

Even if you have 500+ files it takes about ~0.1 seconds to loop through the directory, so whats the problem?

This really isnt a speed issue IMHO.

abbireddy

ThanQ,

I have wrote a PHP to show server directory structure in the client web browser. The server is mainly a backup server. the code I wrote is like below.

function treewalk($T)
{
while($entry=$t->read())
{
if (($entry != '.') && ($entry != '..'))
{
if (is_dir($t->path . "/" . $entry))
{
//do somting.
}
}
}
}

treewalk(<Directory point>);
But the back up server may havesomany files and folders in it. We provide a option for the client to select only folders. so in that case one directory had 70,000 files + 70,001 is the folder. The above PHP is taking hell lot of time to show the tree.

So, I thought it is better to scan only directories instead files is there any way to get the above problem solved.
Thanks in advance.

With Regards
venkat.