PHP Echo Command

doreg28

Sample Code:

<?php echo "
<img scr="banner.gif" height="80" width="468" alt="Click Here">
"; ?>

Instead of putting / before " so the code won't stuff up. Is there another way so that I won't have to put the / before " ??

Since my site is pre made, it would take a long time going through all the " and putting / before them.

Does anyone know a way to get around this?

Any suggestion are welcome!
Thanks for your time, Ye

MeX

hi doreg28!

<?php

echo "<img scr=\"banner.gif\" height=\"80\" width=\"468\" alt=\"Click Here\">";

echo '<img scr="banner.gif" height="80" width="468" alt="Click Here">';


?>

but why you don't like the '\'??

ceeyaa.MeX

doreg28

LOL, thanks alot MeX 🙂

doreg28

As I said, MeX, my site is pre made, and I am too lazy to go through al the " and place / before them.

There must be over 100 " in my site!

MeX

NOTE:

<?php

// WORKS
echo "<img scr=\"$filename\" height=\"80\" width=\"468\" alt=\"Click Here\">";

// NOT WORKING; $filename is a string
echo '<img scr="$filename" height="80" width="468" alt="Click Here">';

// WORKING
echo '<img scr="' . $filename . '" height="80" width="468" alt="Click Here">';

?>

ceeyaa.MeX

doreg28

oic

Thanks again!

you're a real life saver 😃

doreg28

Would this still work?

<?php

// WORKS
echo '<img scr=\"$filename\" height=\"80\" width=\"468\" alt=\"Click Here\">';

MeX

NO!

you should read more carefully!!

$var = 'i am there';

// ' means everything is a string
echo 'hello world $var';
// output ==> hello world $var

// " means string OR var
echo "hello world $var";
// output ==> hello world i am there

// if you want to display ' OR "
echo "hello world it's me";
echo 'hello wold itSLASH's me';

echo "hello \"world\"";
echo 'hello SLASH'worldSLASH'';

// SLASH
// it ignores my slashes so replace SLASH with "\" manually

just copy and paste it into a php-script and execute it on your web-server!!

ceeyaa.MeX

doreg28

ohhhhhhhhhh

I understand now !!

Thanks!

feldon23

Curious why you can't leave the HTML out of the PHP code?

<?php
// various php code here
?>
<img src="banner.gif" height="80" width="468" alt="Click Here">
<?php
// more php code here
?>

If you need to substitute values into the HTML code as you go, you can use the heredoc structure:

$data=<<<QQQ
<img src="{$filename}.gif" height="80" width="468" alt="Click Here">
.
.
.
QQQ;

echo $data;

And with heredoc, you don't even have to do \n for new lines. 🙂

The only drawback of heredoc is that you can only use variables; you cannot execute PHP code/functions within it. So you need to determine the filename and stuff it into a $variable before the heredoc construct.

doreg28

How about this:

<?php

echo '<img scr="' . $filename . '" height="80" width="468" alt="Click Here">

My Page!

<p>

include("body.php");
';

It doesn't include the body.php.
is there anyway of including a file inside "echo" ??

feldon23

Erm, you "include" to have the functions of that PHP file available. You don't include to paste the contents of that file.

<?php

echo '<img scr="' . $filename . '" height="80" width="468" alt="Click Here">

My Page!

<p>

include("body.php");
';

?>

#1 you're not escaping that right.
#2 you can't include like that

<?php
require "body.php";

$data = <<<QQQ
<img src="{$filename}" height="80" width="468" alt="Click Here">
QQQ;

echo $data;

How exactly are you generating $filename? Maybe that will help us. If you want to pull it out of a flat text file then you don't want that text file to be a php file (And you probably don't want it anywhere public on your site). If you are pulling the filename out of a MySQL or other database, then we can look at that too.

doreg28

Your code doesn't work

<?php
include("body.php);

$data = <<<QQQ
<img src="{$filename}" height="80" width="468" alt="Click Here">
QQQ;

echo $data;

It says
Parse error: parse error on line 4

Also
Are you sure there's no way of including a file in echo like that?

feldon23

I was missing a quote on the include above. Actually, you're better to use require.

<?php
require "body.php";

$data = <<<QQQ
<img src="{$filename}" height="80" width="468" alt="Click Here">
QQQ;

echo $data;
?>

Also
Are you sure there's no way of including a file in echo like that?

Can you tell us why you are trying to include a PHP script into an echo statement?

doreg28

Its hard to explain why i want to include a file inside echo statement.

But I'm going to try anyway. say this code:

<?php
echo 'This is my banner: include("banner.txt")
?>

I need to include a file that I will keep changing. I want to use the include feature for easy editing

but then again... I might do it outside the echo statement.

feldon23

See, that's what I thought.

Include does not do what you think it does.

Include allows you to access the functions and modules contained within another PHP script.

If the script "myfunctions.php" contains a function called, say "createworldpeace", then your website would do this:

index.php
<?php
include "myfunctions.php";

// do other stuff

$a=createworldpeace();

// do other stuff
?>

Anyway, that's NOT what you need here. What you need is to grab the contents of a file and insert it into your website.

There are several ways to do this. The most strongly recommended way is to set up a MySQL database on your web account and put the data in there and then pull it out and put it into your website.

As a beginning web designer, you might find it easier to start out using INI files as I did.

Please see the attached file. I'll probably get burned at the stake for posting this because I have slightly modified an existing EXCELLENT script written by jorgen to give it some more functionality. Full props to him, I only added a couple lines and wrote a help file.

So to use this script, just add it at the top of your file like:

<?php
require "inifunctions.php";
?>

and then retrieve information from the INI file with the functions provided.

seby

well if it's a function file then require(); is usually used rather than include();

also, most people don't realize that

echo '$variable';

only echos the "$variable"

If it severs one purpose: echo $variable;
more than one purpose: echo "this is my $variable";

that causes much confusion.

robsgaming

easiest way is to do a global find and replace and leave the code the way you have it

everytime it finds a " simply tell it to replace it with a \"

thats what i always do.. might get a few errors, just go back and fix them as needed.

Weedpacket

Originally posted by doreg28
But I'm going to try anyway. say this code:

<?php
echo 'This is my banner: include("banner.txt")
?>

I need to include a file that I will keep changing. I want to use the include feature for easy editing

but then again... I might do it outside the echo statement.

You'll have to do it outside the echo statement - how's PHP to know you want to run part of the string as PHP code and not just display it? And which bit? (This is why variables are decorated with $ signs.)

<?php
echo 'This is my banner: ';
include("banner.txt");
?>

[i]banner.txt[/i]
<img src="banner.gif" height="80" width="468" alt="Click Here">

feldon23

I did not realize that include/require could also paste the contents of a text file. My bad.

So you can do stuff like this:

<b>I really think that <? include("actress.txt"); ?> 
is a good actress and is really attractive.</b>

actress.txt contains:
Halle Berry