Day of Week Error

[vatic]

I'm trying to create a PHP script that will determine the day of week (monday, tuesday, wednesday, etc), and according to which day it is, a different includes file is loaded. I put this code together, but it doesn't work. I'm extremely new to PHP, so I was wondering if someone could help me out.b

Here's what I have come up with, but first of all it doesn't work, it posts "b.php" as if it was Sunday, when in fact the server date is Tuesday.

<?php

$A = date("D");

$B = "Sun";
$C = "Mon";
$D = "Tue";
$E = "Wed";
$F = "Thu";
$G = "Fri";
$H = "Sat";

$A == $B { require ('/path/to/includes/b.php'); };
$A == $c { require ('/path/to/includes/c.php'); };
$A == $D { require ('/path/to/includes/d.php'); };
$A == $E { require ('/path/to/includes/e.php'); };
$A == $F { require ('/path/to/includes/f.php'); };
$A == $G { require ('/path/to/includes/g.php'); };
$A == $H { require ('/path/to/includes/h.php'); }

?>

[Rohan_Hill]

Instead of

$A == $B { require ('/path/to/includes/b.php'); };

for example, you need

if ($A == $B) { require ('/path/to/includes/b.php'); }

[milind24]

Try this :

$A = date("D");

$B = "Sun";
$C = "Mon";
$D = "Tue";
$E = "Wed";
$F = "Thu";
$G = "Fri";
$H = "Sat";

($A == $B)?require ('/path/to/includes/b.php'):"";
($A == $C)?require ('/path/to/includes/c.php'):"";
($A == $D)?require ('/path/to/includes/d.php'):"";
($A == $E)?require ('/path/to/includes/e.php'):"";
($A == $F)?require ('/path/to/includes/f.php'):"";
($A == $G)?require ('/path/to/includes/g.php'):"";
($A == $H)?require ('/path/to/includes/h.php'):"";

[vatic]

thank you for the help, it works now.

[The_Chancer]

This may sound a little off - but why not rename your b - h.php files Sun - Sat.php, and use

<?php

$dow=date("D");
$file="images/";
$file .=$dow;
$file .=".php";
require $file;

?>

Saves space... and works....

[vatic]

oh yeah, thats kinda cool. Didn't think of it like that. thank you.