replace # sign

[jroscoe]

I have the followig function:

function fill_store_specs($store_numbers) {

 $temp_stores=array();
 $stores=array();

 if (@count($store_numbers) ) {
		$sql_stores="";
		# build a string for our sql query "IN" clause
		for(reset($store_numbers);$key=key($store_numbers);next($store_numbers)) {
			 $sql_stores.="$key,";

		}

		# if we've data, remove the last comma
		if (strlen($sql_stores)) {
			 $sql_stores=substr($sql_stores,0,-1);
		}

		# do database lookup

What I need is, if a user enters a store number like (#3613), I need to replace the # with either a null or 0. How can I do this?

[DigitalExpl0it]

hows this

<?
$var = "#445245";
	$var = eregi_replace("#", "0", $var);
	echo $var;
?>

[jroscoe]

would I put it right after this line:

for(reset($store_numbers);$key=key($store_numbe
rs);next($store_numbers)) {

like this:

$key = eregi_replace("#", "0", $key);

[devinemke]

you don't need regular expressions to do this. simply do:

$var = str_replace ('#', '', $var);

[jroscoe]

and where in my code do I put this? I tried the previous example and I get a store number of 0, not 0 plus the store number.