resource id # 2 or # 3 returned

[aaadispatch]

alright all I just started getting into php mysql combo here and I am getting the following error

$sc = mysql_query("SELECT pass FROM peoplez WHERE user = 'csr' ");

This is simply returning resource ID # 2 I need the actual value of pass returned how do I do this

I can't get any query to return any result at all I get resource id # 2 or resource id # 3 everytime I try to get something from the database - any help?

[Lars_Berg]

read the docs. start at mysql_fetch_array.

[aaadispatch]

I looked through the online doc and the manual html file that is included with the database itself and I can't even find anything about mysql_fetch_array

If I am just completely blind and it is indeed in there could you point me to it or somewhat explain what I missing?

Thanks

[Lars_Berg]

http://www.php.net/manual/en/function.mysql-fetch-array.php

mysql_query returns a handle that is passed to mysql_fetch_array for fetching individual records from the result.

[aaadispatch]

Thanks man I was looking in the mysql docs - not the php docs - lets hope this helps

[aaadispatch]

Thank you very much for your help and it works now - thanks again

[aaadispatch]

Thank you very much for your help and it works now - thanks again