Eval question...

kj2w27513

How can I convert this to work with the eval function?

$myArray[ $myRow["col1"] ][ $myRow["col2"] ] = 1;

???

Jason

ps. I posted this question in the 'NEWBIE' section and nobody has answered it. So it looks like this is a pretty active forum so thats why I posted here also.

eoghain

$myRow["col1"] = 1;
$myRow["col2"] = 1;
$str = "$myArray[ $myRow[\"col1\"] ][ $myRow[\"col2\"] ] = 1;";
eval $str;
echo $myArray[1][1];

That should work, what have you tried and what are your results?

kj2w27513

Would this work?

$myRow["col1"] = 1;
$myRow["col2"] = 1;
$str = "$myArray[ $myRow[\"col1\"] ][ $myRow[\"col2\"] ] = 1;";
eval $str;

$newStr = "echo $myArray[ $myRow[\"col1\"] ][ $myRow[\"col2\"] ];";

echo $newStr;

???

jason

eoghain

Yes what you typed would work if you wanted this result:

echo $myArray[ $myRow[\"col1\"] ][ $myRow[\"col2\"] ];

If you want to have $newStr print out itself then you need to eval() it again not just echo it.

kj2w27513

Shoot!!! this is what i meant to say:

$newStr = "echo $myArray[ $myRow[\"col1\"] ][ $myRow[\"col2\"] ];";

eval($newStr);

Now, you think this would print what ever was in $myArray[1][1] ??

jason

Weedpacket

Well, the code to echo the value of $myArray[ $myRow["col1"]][$myRow["col2"]] is

echo $myArray[$myRow["col1"]][$myRow["col2"]];

To run that through eval(), you wrap quotes around it to make the string. You'll want to use single quotes, otherwise PHP will try and interpolate all those variables before evaluating. Probably not what you want (though it may appear to work, it would be for the wrong reasons - which would cause grief later).

eval('echo $myArray[$myRow["col1"]][$myRow["col2"]];');