exiting a method

[Nuno]

Hi

Let's say i'm using a class
Class one
{
function method1(){
.......
if ( condition ){
return 1;
(exists from method without executing the remaing code)
}
........
}

}

What i want is to call the method and, if the condition is true,
it returns 1 and exits from the method without executing the remaining code from the method.
I want it to execute the rest of the code from the program.

Thanx in advance

Nuno

[d-Pixie]

If the function is not a constructor (or maybee even then?) if you have the class defined as above and a object created from it (IE. example). Then a call to $example->function(); would do as you want if the function is propperly defined:

function function(); //reservation for the reserved word function ;o)
{
if (condition) { ... return 1} else {return 0};
}

or:

function function();
{
if (condition) {... return 1}
else if (another_condition) {... return 2}
else return 0;
}

The function will now execute and check the conditions. If they are met it returns the appropriet value else it returns 0 ... (Am I right?)

[Nuno]

yes you are right.

But i don't want to do that.
I want to do something like error catching
I don't want to use a lot of if-else and don't want to test unnecessary conditions.

[Nuno]

Got it

When you do "return" it exists the function and doesn't execute the following code.

Thanx anyway

Nuno

[diego25]

I want to do something like error catching

PHP 5 (i.e. Zend Engine 2) will include try-catch blocks 🙂

Diego