Can't get the coding right.

[Sir_AL]

I want to create something like this, were it puts different things into the table as it outputs. Like one row it will include recipe 1, 2, and 3 and the next row could have recipe 1, 2, 3, 4, 5, and 6 depending on what "recipe =="
The problem is I keep getting this error message.

Parse error: parse error, expecting T_STRING' orT_VARIABLE' or `T_NUM_STRING' in home/mysite/mysite on line 202

Line 202 = elseif ($myrow["recipe"] == "1"){$myrecipe = "$myrow['recipe1']";}

$result = mysql_query("SELECT * FROM $table ORDER BY $sort");
	if ($myrow = mysql_fetch_array($result)) {
		  ?>
 <center><table border=1 width="1191">
 		 <tr>
 		 <td width="248"><font color="#800080"><center><b>Name</center></td>
 		 <td width="41"><font color="#800080"><center><b>Level</center></td>
 		 <td width="210"><font color="#800080"><center><b>
 		 <?php
 		 if ($table == "ore")
 		 {echo "Refining Cost";}
 		 else {echo "Manufactuing Cost";}
 		 ?>&nbsp;</center></td>
 		 <td width="178"><font color="#800080"><center><b>
 		 <?php
 		 if ($table == "ore")
 		 {echo "Harvesters";}
 		 else {echo "Builders";}
 		 ?>&nbsp;</center></td>
 		 <td width="306"><font color="#800080"><center><b>Notes and Abilities</center></td>
		 <td width="360"><font color="#800080"><center><b>Recipe</center></td>
 		 <td width="112"><font color="#800080"><center><b>Time Created</center></td>
 		 </tr>
 <?PHP
  do {
	if ($myrow["recipe"] == "0"){$myrecipe = "No Recipe";}
	elseif ($myrow["recipe"] == "1"){$myrecipe = "$myrow['recipe1']";}
	elseif ($myrow["recipe"] == "2"){$myrecipe = "$myrow['recipe1'].', '.$myrow['recipe2']";}    

	elseif ($myrow["recipe"] == "3"){$myrecipe = "$myrow['recipe1'].', '.$myrow['recipe2'].', '.$myrow['recipe3']";}
	elseif ($myrow["recipe"] == "4"){$myrecipe = "$myrow['recipe1'].', '.$myrow['recipe2'].', '.$myrow['recipe3'].', '.$myrow['recipe4']";}
	elseif ($myrow["recipe"] == "5"){$myrecipe = "$myrow['recipe1'].', '.$myrow['recipe2'].', '.$myrow['recipe3'].', '.$myrow['recipe4'].', '.$myrow['recipe5']";}
	elseif ($myrow["recipe"] == "6"){$myrecipe = "$myrow['recipe1'].', '.$myrow['recipe2'].', '.$myrow['recipe3'].', '.$myrow['recipe4'].', '.$myrow['recipe5'].', '.$myrow['recipe6']";}
	else {$myrecipe = "Error, Contact AL";}
    printf("<tr>
    <td width=248>%s&nbsp;</td>
    <td width=41>%s&nbsp;</td>
    <td width=210>%s&nbsp;</td>
    <td width=178>%s&nbsp;</td>
    <td width=306>%s&nbsp;</td>
    <td width=360>%s&nbsp;</td>
    <td width=112>%s&nbsp;</td>
    \n",$myrow["name"], $myrow["level"], $myrow["manufacturing_cost"], $myrow["builders"], $myrow["special_notes"], $myrecipe, $myrow["time"]);
  } while ($myrow = mysql_fetch_array($result));
	echo "</table></center>\n";

[bastien]

1. don't think you need the quotes around the 1 in the check
2. don't think you need the quotes around the $myrow['recipe1']

elseif ($myrow["recipe"] == "1"){$myrecipe = "$myrow['recipe1']";}

maybe should look like this

elseif ($myrow["recipe"] == 1){$myrecipe = $myrow['recipe1'];}

might also consider switching to [man]SWITCH [/man] to make things easier

also could try coding the extras into a loop based on the value of $recipe

[Sir_AL]

Thank you that worked perfectly, the quotes were the problem.