Get position of image to place Popup menu

[Cherphas]

Hi,

Is there a way to get an image's position on the screen?

What I want to do is generate a side menu from a database. I want each Link in the menu to have a pop up menu(CSS layer), and the content of this popup menu would be database driven also. To position the popup menu to their respected links, I though I would place a transparent gif beside each link, get its position and place the layer at that position. So I figured the logic would go like this:

Connection Strings

SELECT Titles FROM table1
WHILE loop to display title
     <td>
          display title
     </td>
     <td>
          transparen gif, 1 x1 pixel(I want to position the Popup menu here, so I would need its position at this point)
     </td>
     Create layer at position of gif
    SELECT Subtitles which matches with current title from table2
     While loop to display all Sub-titles in popup menu
          display subtitles
     loop
loop to display next titles

Does this make any sense?

[Cherphas]

Nobody? I got the layers thing working, I got a function to get the images position, I'm just not sure how to call it. somebody said Onload, but how does the function know which image to process? Do I put it in the image tag?😕

[jerdo]

This is a php forum and what you are trying to do seems to deal more with java-script, that's why you aren't getting any answers.