comparing a variable to array

[The_Walrus]

I need to know how to compare a variable to an array and if it is == to any of the values do 1 thing and if it != any of the values do another. The problem right now is it does one thing or the other each time it checks the variable vs each of the array.

ie.

for ($a; $a < $b; $a++)
{
  if ($some_variable == $some_array[$a])
 {
   echo "its equal<br>";
 } else {
   echo "its not equal<br>";
 }
}

if $b is say 5, this would basically say

its not equal
its not equal
its equal
its not equal
its equal

when I would really want just

its equal, if that does not make sense i can post my code to see exactly what is going on.

[siwis]

for ($a=0; $a <= $b; $a++)
{
  if ($some_variable == $some_array[$a]) {
   $pass = 1;
 };
}
if ($pass==1) {
  echo "its equal<br>";
} else {
  echo "its not equal<br>";
};

[The_Walrus]

i will test this out and see if it workd how i am hoping, the newbie forum is so much more helpful then the coding forum...lol

[kristianblom]

In this case you should definetely use the in_array function.

if(in_array($variable, $array)){
do something ...
}else{
do something else ...
}

[The_Walrus]

but to update my status it didnt work

for ($y=0; $y<sizeof($dateList); $y++)
{
if ($dateList[$y]== sprintf("%02d", $dcv))
{
 echo $dateList[$y]."<br>".sprintf("%02d", $dcv)."<br>";
 $bcv = "silver";
} 
else 
{
 echo $dateList[$y]."<br>".sprintf("%02d", $dcv)."<br>";
 $bcv = "red";
}
}
echo "<td align=center bgcolor=".$bcv."><font face=Arial size=-1>".$dcv."</font>";
echo "</td>\n";

this almost works, i echoed out every comparisons, and for example one of the values is 02, and there is a 02 in the array but when it prints the 02 cell it prints red, in fact the only one that doesnt is 30, and the array contains about 20 days, but i will now try the in array thanks again for the help?

[The_Walrus]

thanks the inarray really made it a million times easier and is working great