copy confusion

[ElectricMessiah]

Hi,

I have had some issues with trying to copy an image from a website to a local directory.

$fp = fopen($image_url, 'rb');
if (!copy($src_file, $dest_file)) {
echo "failed to copy $src_file...<br>";
}

I get the following error:
Warning: Unable to open '[the url]' for reading: Invalid argument in ... [script location]

I know there is a way but, I must be missing something.

Thanks!

[drtebi]

Hey there,
the copy() function does only allow copying of URLs with PHP version 4.3 or later... refer to the manual page.

Anyway, you can copy an image from a URL like this:

<?php
$src_file = 'http://www.php.net/images/php_logo.gif';
$dest_file = 'php_logo.gif';

// get image
$fp = fopen($src_file, 'rb');
$image_data = fread($fp, 100000);
fclose($fp);

// write image data to local disk
$fp = fopen($dest_file, 'wb');
fwrite($fp, $image_data);
fclose($fp);

?>

Peace,
DrTebi