Finding a quote in string

[robertaccettura]

How does one check string $string to see if it contains a quote """

This is what I came up with:

				preg_match("/[^\"\/]/i", $value, $quoteCheck);

But doesn't seem to be right

[mahers]

preg_match("/\"/",$string,$quoteCheck);

Is that what you mean?

[robertaccettura]

Tried that, but doesn't find anything for some odd reason.

[mahers]

Can you give an example of what the $string contains?

[robertaccettura]

the string contains the following line:

"this is good"

with quotes on either end.

but sometimes contains

this is good

no quotes.... so it needs to know if quotes are there or not.

[RedDragon]

hi, you might try this:

$name = "\"Thomas\"";
if(strstr($name, '"')){
echo "this name is not allowed";
}

[robertaccettura]

I can't just give an error. If quotes exist, I need to substr() to remove the quotes from each end. If not, I don't want to cut off the text.

[diego25]

Then use trim():

$string = trim($string, '"');

Diego

[robertaccettura]

Thanks, but can't replace all occurances.

What if there is a quote within the string itself? That needs to stay.

[mcgruff]

strchr()?

Sounds like you don't have the manual - it's an essential download.

[Weedpacket]

if(preg_match('/^".*"$/s', $value)
    $value = substr($value,1,-1);

The s being there if there's a chance that a linebreak will appear in the string. If there's no such chance, it's unnecessary.