Grabbing a version # from a URL

[rheroux]

Okay, I've searched around and found some good examples, but now I'm stumped.

I'm trying to grab a version number of an application off of a website, and then stick that into a variable so I can compare it with the link I have and have it dynamically updated to show the newest version.

Here's the code I have thus far:

<?php

$url = "http://www.someurl.com";
$content = join('',file($url));
$length = strlen($content);
$startstring = strpos($content,"Super Duper App");
$endstring = strrpos($content,eregi("Version [0-9][0-9][0-9]",$content));

$tempresult = substr($content,$startstring,$endstring);
$appversion = substr($tempresult,-3,3);
echo $appversion;
?>

The problem is that $tempresult holds all the html code from the last strrpos index and onward. I'm sure it's blatantly obvious to some of you gurus out there. 😉

Any help is appreciated.

Note: Oh, and I know that the regexp there isn't foolproof, but the software is currently at v109, so I doubt they're going to hit v999 anytime soon. 🙂

[diego25]

Try this:

<?php
$url = "http://www.someurl.com";
$content = join('',file($url));
preg_match('/Version (\d{3,})/', $content, $matches);
$appversion = $matches[1];
echo $appversion;
?>

That will also handle versions with more than 3 digits.

Diego

[rheroux]

Well, I got it to work, but I ended up using ereg rather than preg_match.

Yes, yes, I know, preg_match is faster, but I'm a lot more familiar with ereg. 🙂

[statrat]

you could also try:

$content_without_html = strip_tags($content);

[diego25]

There should have been a backslash before the 'd' in the regexp. For some reason this forum removes the backslashes...

Diego