Numbers again

[ishbo]

I need a function that will allow me to take an unknown number and use it as a variable. The application is that i have a form with 30 places to type a number, and i want to have my formula not screw up if all the spots are not filled in. So, the if the person uses say 5 out of 6 spots, the forumla needs to be able to say:

(testg1 + testg2) / $testnum;

where $testnum would equal 5 in this case, or any number up to 6.

[LordShryku]

Hrmm....I think what you need to do is to setup if statements to set it to zero if a place on the form wasn't filled in...

if(/(bb|[^b]{2})/) { echo "That is the question..."; }
if(!$testg1) { $testg1 = 0; }
if(!$testg2) { $testg2 = 0; }
if(!$testg3) { $testg3 = 0; }

and so on...

[ishbo]

LordShryku,
If i do that, then my formula will be wrong. I will have for instance, a (100 + 95 +96 + 0) / 4; which gives you a wrong answer. Is there more i can do?

[ishbo]

Good idea, but not quite what I need. My form takes averages, so I need to be able to divide the sum of the entered numbers by the number of numbers entered. Whew, tongue twister...

[Teen0724]

have something like this

$count=0;
if (!$item1) { $item1 = 0; $count++; }
if (!$item2) { $item2 = 0; $count++; }
if (!$item3) { $item3 = 0; $count++; }

$answer = (($item1 + $item2 + $item3) / $count);

That should do what you wanted to.

[ishbo]

Thank you. Could someone explain that to me?

I understand most of it.

Does the $count++ add 1 to the count if there is a value entered in that item?

Each filled in value must add 1 to the $count.

[ishbo]

Here's a link to the current file in case that will help:

http://cdc.frontiernetcom.com/PHP/gradecalc.php

Not too great looking yet. I'm still working on it obviously.

Thanks all.

[Tracer]

Or you could add all the vars which were submitted into an array.

Then you can use array_count, array_sum etc etc...

Check out the array functions at www.php.net

[ishbo]

Thank you. Seems like it should work. I will put it into my code asap.

[ishbo]

Anyone else have more ideas on what to use, or on how to use the array_count function?

[Tracer]

the two functions you will need are

array_sum();
http://www.php.net/manual/en/function.array-sum.php

and

array_count_values();
http://www.php.net/manual/en/function.array-count-values.php

$mySum=array_sum(MyNewArray);
$myCount=array_count_values(MyNewArray);
$myGrade=($mySum/$myCount);

[Teen0724]

$count++ is the same $count = $count + 1;

its easier.

[ishbo]

I entered this code into my file:

$mySum=array_sum("$testg1" , "$testg2" , "$testg3" , "$testg4" , "$testg5" , "$testg6");
$myCount=array_count_values("$testg1" , "$testg2" , "$testg3" , "$testg4" , "$testg5" , "$testg6");
$myGrade=($mySum/$myCount);

echo "$myGrade";

and the page returned this:

Warning: Wrong parameter count for array_sum() in c:\apache\htdocs\grade.php on line 8

Warning: Wrong parameter count for array_count_values() in c:\apache\htdocs\grade.php on line 9

Warning: Division by zero in c:\apache\htdocs\grade.php on line 10

Line 8 is the $mySum= line, line 9 is the $myCount= line, and line 10 is the $myGrade= line.

I really have tried most of the things in my knowledge to fix this, and none work.