Capture Return code of Preg_Replace?

[4rxsid]

Hi all,

Im using preg_replace to successfuly replace anything found in the search array:

$search = array ("'a'", "'b'", "'c'");
$replace = array ("","","");

$text = preg_replace ($search, $replace, $document);

This works great.
My question is, how to I capture, or test for the successful return of this function? In other words, if something is found and replaced, will $text = 1? or will $text = "True".

I want to be able to get the return code of this function, to be able to display some info after the fact.

Thanks.

[spirp]

According to the PHP manual:

[FONT=courier new]If matches are found, the new subject will be returned, otherwise subject will be returned unchanged.[/FONT]

Read more about the function at: http://www.php.net/manual/en/function.preg-replace.php .

If you want to know if anything was replaced, I guess you can match the two string to each other, if they're the same, nothing has changed, otherwise it has..

$subject1 = "abcdefabcdef";
$subject1 = "klmnopklmnop";
$replacement = Array('A', 'B', 'C');
$pattern = Array('a', 'b', 'c');

$result1 = preg_replace($pattern, $replacement, $subject1);
$result2 = preg_replace($pattern, $replacement, $subject2);

if ($subject1 != $result1) {
    echo "subject1: replaced\n";
} else {
    echo "subject1: no replace\n";
}

if ($subject2 != $result2) {
    echo "subject2: replaced\n";
} else {
    echo "subject2: no replace\n";
}

this ought to generate the output:
[FONT=courier new]subject1: replaced
subject2: no replace[/FONT]

(sorry if the code above is incorrected or misspelled or what ever, my host is down right now, so I can't verify it..)

Good luck,
Olle