Get page name with PHP

I'm sure there is an easy answer, but I cannot find it in the manual.

I have a script in a folder on my site and I want to get the page name from the script. I am using

====
$this = $REQUEST_URI;

Print "$this<br>";

However, this will print the folder name also. Example, if this page is http://www.somedomain.com/folder2/script.php , the output is "/folder2/script.php".

I want to receive output of the "page name" only. Ex. "script.php". The folder names change so there is no easy way to strip the folder name.

What am I missing? Any suggestions?

$page = $_SERVER['PHP_SELF'];
echo $page;

Originally posted by mahers
$page = $_SERVER['PHP_SELF'];
echo $page;
[/B]

Thanks for the effort, but no. That returns

"/folder2/script.php"

because it lists everything up-to the root directory.

Try

$page = $_SERVER['PHP_SELF'];
$page = substr($page,1,50)//50 incase of long file name, whatever number there
$page = strtok($page, "/");

I didn't try it but I think that should work... 🙂

Terribly sorry I completely forgot it showed the full path to the script. Heres an preg_match attempt.

$f = "/folder2/blah/smeg/script.php";
preg_match("/.*\/(.*\.php)/",$f,$matches);
echo $matches[1];

Instead of using $f just use the PHP_SELF variable.

The basename function does exactly what you want.

Originally posted by sutra
The basename function does exactly what you want.

"basename". That's exactly what I was looking for! Thanks.

Thanks to everyone who contributed ideas. I appreciate it.

Bill