read out dir

[Absinthguru]

hi,

i need a script, which can read out a directory.
after that the script should list all files.

thanks for help.

absinthguru

[jpmoriarty]

this is a script i use a lot - it's for doing links automatically on my site, but you can take out those bits (like the "stripping the html" etc) if you dont need them.

<?php

$handle = opendir('./context') ;   

// Open the directory

$file = readdir($handle);          

$file = readdir($handle);
// The first two folders are . and .. - ignore these

while ($file = readdir($handle)) {
   $file = ereg_replace(".html","",$file);     

   // Remove the .html from the filename
   if ( substr($file,0,1) == "-") {            

   // Only print out the link if there is 
   // a - at the start
      echo "<a href=";
      echo "$file";                            

      // Print out the link HTML code
      echo ".html>";
      // The following characters are changed
      // when actually printing out the link text
      // so spaces can be used etc.
      $file = ereg_replace("-","",$file);      

      $file = ereg_replace(",","'",$file); 
      $file = ereg_replace("_"," ",$file); 
      $file = ereg_replace("~",",",$file);
      echo "$file";
      // Print the hyperlink text
      echo "</a><br>";
      // Close the <A> tag.
   }
}
closedir($handle);?>

[sarah]

I may have misunderstood, but it looks as though you just want to print out the names of all of the files that are in a directory. If so, try...

<?
$dir = @opendir(".");
while (($file = readdir($dir)) !== false) {
	print("$file<br>");
}
closedir($dir);
?>