opendir()

[PaulaRun]

Exactly what goes in opendir()??

This is what I have:

<?php
if ($handle = opendir('root/images/cardimages/')) {
    echo "Directory handle: $handle\n";
    echo "Files:\n";

 while (false !== ($file = readdir($handle))) {
    echo "$file\n";
}

closedir($handle);
}
?>

And I get warning opendir(root/images/cardimages/) failed to open dir: No such file or directory in /home/site/public_html/listpics.php

What should I put in opendir()??

I even tried the whole url/images/cardimages and that didn't work either.

[WinterDragon]

Try putting double quotes around the dir name, also... what directory are you in when you try to use the func like that?

[PaulaRun]

I tried the double quotes - doesn't work.

I don't know what directory I'm in - how can I tell? I just have a page that includes a php script that is trying to read the contents of the image file.

How can I find the path for the opendir()??

[diego25]

The error message tells you where you are:
/home/site/public_html

What's the path of the directory you're trying to open? I'm pretty sure it doesn't start with root...

Diego

[PaulaRun]

You're right. I got it to work with this:

opendir("./images/cardimages")

Thanks!