Php class links

[liquidchild]

I have created an intranet site, and am looking to create a new php class called phone, which searches a phone directory, however can i call this from a form with parameters or make it a link, for example i am not sure how to get the equivalent on phone.php?content=surname (link) if phone is a class?

[Mordecai]

I'm not quite sure I understand. Can you rephrase the question?

[liquidchild]

Ok, hope this makes it clearer!

I have a class called phone.class.php, code shown below:

<?php

session_start();

include_once( "../layout/layout.class.php" );
include_once( "../../navigation/navigation.class.php" );

class phone
{
/ The layout class /
$var $_layout;

function phone( $searchType )
{
	/** Create a new layout class **/
	$this->_layout = new layout();

	/** Display the search form **/
	$this->_displaySearchForm( $searchType );
}

/** Displays the search form to the user, depends on searchType **/
function _displaySearchForm( $searchType )
{
	/** Display the search form **/
	$this->_layout->newLine(true);
	echo "<form action= '' method= 'post'>";

	$this->_layout->newLine(true, 2);
	echo "<label for= 'searchType'>Please Enter $searchType: </label>";

	$this->_layout->newLine(true, 2);
	echo "<input type= 'text' id= 'searchType'>";

	$this->_layout->newLine(true, 2);
	echo "<input type= 'submit' value= 'Search'>";

	$this->_layout->newLine(true);
	echo "</form>";
}

}//End Phone

?>

I want this to be a link on my website. I am aware that if this were not a class file i could just do phone.php?content=surname and this would produce a form that could be used to search for a surname. However since this is a class and I require to instansiate it i am not sure what to do. Am i going about this wrong. I don't want to over complicate matters!

Cheers

[Mordecai]

Have, perhaps in a separate file, a conditional statement check if content=surname. This file would include phone.class.php, and would use the class functions to search.

I think that's what you're looking for.