Help with incorporating php

olygolfer

Hi is there anyone that cn help me incorportae this Html code into my php. Whenever i try to incorprate it it apperas with the statement

( " ' could be missing or expected)

the html is below ive seperated the lines for easier reading

<?php

echo "<table width="100%" border="0" cellspacing="0"
cellpadding="0">";

echo "<tr>";

echo "<td colspan="3"> </td>";

echo "</tr>";

echo "<tr>";

echo "<td width="2%"> </td>";

echo "<td width="45%"><div align="center"><img src="PC%20Shop/images/pic_prod336_lang1.jpg" width="174" height="120"></div></td>";

echo "<td width="53%" class="Text1"></td>";

Ive got a feeling that it is probabaly caused by the values of the table but i am not sure how to correct it

Any help you be great thanks

oPt1k

Try this, couldn't be bothered explaining what you did wrong, you should be able to see for yourself!

<?php

echo "<table width="\100%\" border=\"0\" cellspacing=\"0\"
cellpadding=\"0\">";

echo "<tr>";

echo "<td colspan=\"3\"> </td>";

echo "</tr>";

echo "<tr>";

echo "<td width=\"2%\"> </td>";

echo "<td width="\45%\"><div align=\"center\"><img src=\"PC%20Shop/images/pic_prod336_lang1.jpg\" width=\"174\" height=\"120\"></div></td>";

echo "<td width=\"53%\" class=\"Text1\"></td>";

olygolfer

Thanks for the help.

I have one more quick question. Instead of uploading the image files to a blob on mysql i have decided to upload the url of the image instead.

Once the php script is activated the query can search a product and bring the details to the page, so the image url is stored in the variable example: $image.

Is it possible to replace the image src value with the variable $image so once it is read the image is collected from the url in the variable

echo "<td width="\45%\"><div align=\"center\"><img src=\"PC%20Shop/images/pic_prod336_lang1.jpg\" width=\"174\" height=\"120\"></div></td>";

thanks once again

Mordecai

Here's a way that may be more useful to you:

echo <<<END
This is <html> that <a href="can">use</a> quotes.
END;

As for your second question, I'm not quite sure what you mean. Do you just want to echo a variable inside the HTML? If so, just simply write it as you normally would.

olygolfer

Hi
It might be a little easier if i explain it this way

a search is placed on mysql and the url of the image wich is stored on the msyql table is stored in the variable $image

exampl $image = www.mydomain.com

The image code placed within the php code on the web page would be set up like this

echo "<td width="\45%\"><div align=\"center\"><img src=\" $image \" width=\"174\" height=\"120\"></div></td>";

so this would fetch the image src from url within the variable

Would it work like this

Thanks

Mordecai

Yeah, that would work fine, if it were to know what $image will be, which it might not, depending on your code.