Problem in "if" evaluting a string?

[bsmith]

here is my code:
<?php
foreach( $offers as $o )
{
print $o["thumbnail"];
?>
<?php if( $o["thumbnail"] ):?>

<br> <img src="<?php print $o["thumbnail"];?>

<? else: ?>

No Image

<?php endif;?>

<?php
} // end foreach
?>

My Results:

thumb1.gif
No Image
thumb2.gif
No Image

The array value $o["thumbnail"] has a value, and the value will print, but

if( $o["thumbnail"] )

evalutes to false

php 4.3.1 on Redhat 7.3

thx
B

[planetsim]

Try using { and } instead of :

[batman]

I don't know if this will work, but you can try. I beleive that the if statement your are calling is set to false. So basically you are saying if there's nothing there pring image, but else if it't not print No image. Try using this:

foreach( $offers as $o ) 
{ 
print $o["thumbnail"]; 

if(isset($o["thumbnail"]))
{
echo "<br> <img src='$o['thumbnail']'>";
}
else
{
echo "No Image!";
}
}

Please, anybody, correct me if I'm wrong!
-Blake

[bsmith]

I tried using isset(), too, no luck.

Also, I tried:

if( $o["thumbnail"] )
{
     $o["thumbnail"] = "<img src=\"" .            $o["thumbnail"] . "\">"; 

}
else
{
     $o["thumbnail"] = "No Image";
}
print $o["thumbnail"] . "<br>";

I get all "No Image", and no images, but I can look at the data in the database and just do a print statement and see that there are values in my $o["thumbnail"] variables.

[batman]

Just eliminating our options. Try using this:

foreach( $offers as $o ) 
{ 
$var = $o['thumbnail']; 

if(isset($var) && ($var > 0))
{
echo "<br> <img src='$var'>";
}
else
{
echo "No Image!";
}
}

Let me know what you get!
-Blake