Having a problem with strpos()

I don't get why this doesn't work.

I have a field called $weekday in my db, type = varchar
I fill it with a value - "a" (no quotes)
I echo $weekday and it says "a"
I write

if (strpos($weekday, "a") !=false) {
echo "blarg";
}

and I get nothing.

I also tried simply

if (strpos($weekday, "a")) {
echo "blarg";
}

and still nothing.
Seems like it should work...any clues?

You need to use three equal signs "===" identical to. This means that the letter was not found.

Your strpos function is working it is just returning 0 the position of the letter a in the string. Try the following:

if (strpos($weekday, "a") !== false) { 
echo "blarg"; 
}

You need to differentiate between strpos returning position 0 and 'false' by checking with the 'identical to' operator which test value and type.

ie '===' or '!=='

if (strpos($weekday, "a") !== false) {
echo "blarg";
}

hth

Perfect - thanks!