Problem echoing array

[micmac]

Hi all,
Can anyone tell me why i'm getting the following error?

Warning: Invalid argument supplied for foreach() in /usr/local/etc/httpd/sites/kosbab.org/mystiquemodels.net/htdocs/admin/admin.php on line 13

I'm trying to echo the results of an array.
The following code is on the page called admin.php
Here is the form that passes the results:

<form method="post" action="admin.php">
<p><strong>Current Positions:</strong> <br>
<table width="100%" border="0" cellspacing="0" cellpadding="0">

<?
$result_pos = mysql_query("SELECT lady_id,first_name,last_name FROM ladies");
$total_pos = mysql_num_rows($result_pos);

while  ($row_pos = mysql_fetch_array($result_pos)) {

$lady_id[] = $row_pos["lady_id"];
$first_name[] = $row_pos["first_name"];
$last_name[] = $row_pos["last_name"];
}
$num = 1;
while ($num <= $total_pos){
?>
    <tr>

<input name="lady_id" type="hidden" value="<? echo $lady_id[$num-1]?>">
<td><? echo $first_name[$num-1] ?></td>
<td><input name="last_name" type="text" value="<? echo $last_name[$num-1]?>"></td>
</tr>
<?
$num++;
}

?>

</table>
<br>
<input name="total_pos" type="hidden" value="<? echo $total_pos ?>">
<input name="update_position" type="submit" value="Update">
</form>

...and this is what i am trying to echo:

foreach($lady_id as $k,$v){  

    echo "$lady_id[$k] $last_name[$k]<br>";
}

Can anyone see why i would be getting this error?

Cheers,
micmac

[planetsim]

Im pretty sure its gotta be this

foreach($lady_id as $k => $v)

[micmac]

Thanks for the reply planetsim.

I tried that before but i continue to get the same error.
Any more ideas for a solution?

Cheers,
micmac

[cgraz]

do you have globals set to off? If so, try using $_POST['lady_id'] in your foreach.

Cgraz

[micmac]

try using $_POST['lady_id'] in your foreach.

Still getting the same error. Now i'm really confused 😕

Any more ideas?

Cheers,
micmac

[deuce868]

have you tried this out?

foreach($lady_id as $k)
{ 
    echo ($k . " is the answer <br>");
}