explode or preg_split

djkanebo

hey

i am gettin values for a variable.

These values are paths to a file such

C:\temp\temp2\a_folder\file.txt

C:\temp\temp2\temp3\temp4\a_folder4\file.txt

I need to get the last part of the path after the last backslash, i.e., the file name...

does anyone know what the best way to do this is?

xeq

basename: http://www.php.net/basename

djkanebo

is it possible that only works for forward slashes?

xeq

On Windows, both slash (/) and backslash () are used as path separator character. In other environments, it is the forward slash (/).

djkanebo

$carpic holds c:\temp\temp2\a_folder\car.jpg

// gets car.jpg from c:\temp\temp2\a_folder\car.jpg
$filename = basename ($carpic);

I use basename as you say yet when i insert $filename inot the DB it still inserts the full path

xeq

Is it "c:\temp\temp2\a_folder\car.jpg" or "c:\temp\temp2\a_folder\car.jpg"? Backslahes must be escaped. Try to echo the variable and see if you get the right string.

djkanebo

u r right... its

C:\tempw\a.txt

so how do I get around this??

thanx for your help mate ;-)