Dynamic Array Path's

chekote

Is there any way to create a dynamic array path?

I have tried to do it with a variable, but it doesnt seem to work:

e.g.

class ArrayPath
{

function ArrayPath()
{

$Test[Address][Line1] = '2067 Hampton St';

$Path = 'Test[Address][Line1]';

echo $this->$Path;

} // end of function

} // end of class

$Object = new ArrayPath;

prints nothing.

However I am using exactly the same technique to do dynamic function calls.

e.g.

class DynamicFunction
{

function DynamicFunction()
{

$Field_Type = 'Phone';

$Validation_Call = 'Validate_' . $Field_Type;

$this->$Validation_Call();
} // end of function

function Validate_Phone()
{
echo 'success';
} // end of function

} // end of class

$Object = new DynamicFunction;

prints 'success';

I am using PHP 4.3.1.

Thanks in advance.

codeDV

echo $this->$Path; --- Is pointing to a class property. The property "path" does not exists in the class you created becuase you didn't declare it in the class header i.e:

class {
  var $path;

.....
}

Try echo ($path) on its own as this is pointing to the local variable inside the function which I assume is the one you want to print.

chekote

It is not meant to exist within the class.

If it was within the class I would have done:

echo $this->Path;

But I dont want to echo Path, I want to echo the class variable thats name is contained within Path. (test[Address][Line1]);

That is why there is a $ before path, because its being replaced by the contents of path and not being accessed as a class Variable.

It should work. It works fine for function calls......

codeDV

Sorry I see what you are trying to do now. Looks like I'm blind 🙁.

What it is doing is interpreting the: Test['Address']['line1'] as a class property so its looking for a variable with the declaration var Test['Address']['Line1'];.

I am baffled though. I don't know how to get it to see that Test is an array. I will have another look tommorow and see what I can do.

codeDV

I've solved it:

<?php
class ArrayPath 
{ 
  var $Test = Array();

  function ArrayPath() 
  { 

$this->Test['Address']['Line1'] = '2067 Hampton St';

$Path = "Test['Address']['Line1']"; 

eval("\$ret = \$this->$Path;");
echo ($ret);

  } // end of function 

} // end of class 

$Object = new ArrayPath; 
?>

I used the eval() function to force PHP to interpret the whole string as an array and assigned the value of the property to the variable $ret.

Make sure you use qutoes with the arrays i.e ['Address'] NOT [Address] oherwise it messes up again.

chekote

Thanks! Your a Genius.

That looks like a really useful function, didnt know that one existed.

Bet it can make for some confusing code though...