passing LONG variables

fluShaggy

Alright... I feel like an idiot for not being able to pull this off...

I have created a thumbnail generator for a graphics site I own, and the generator works quite well. All it needs to function is the string $image which is equivalent to the filepath.

however, when I call up the html "<img>" tag and set src as

src="th_gen.php?image=../amg/amg_01_800.jpg"

, the string $image never reaches the thumbnail generator... instead I get the error.

Warning: getimagesize: Unable to open '' for reading. in c:\phpdev\www\websites\temp\ba v5.0\temp\inc\th_gen.php on line 3

Warning: imagecreatefromjpeg: Unable to open '' for reading in c:\phpdev\www\websites\temp\ba v5.0\temp\inc\th_gen.php on line 8

Warning: imagecopyresized(): supplied argument is not a valid Image resource in c:\phpdev\www\websites\temp\ba v5.0\temp\inc\th_gen.php on line 11

and quite a bit more. Can anyone help?

jpmoriarty

i usually split it so i have two variables, $directory and $file, and i havent had any problems of that nature. try doing that and obv recombining them in the makeimage page.

also as an afterthought, are you sure you have globals on? you might find it more reliable to refer to $_GET['image'] instead of just $image.

khaldryck

in your th_gen.php
echo $image
you'll see if something is missing that way.

i think the prob is that the path to the image must be from the script as it is an src.
and the path you gives is relative to the page calling that src.

ex :
your script is in /www/index.php
your th_gen is in /www/inc/th_gen.php
your pic is in /amg/pic.jpg

from the script : you access the pic using ../amg/pic.jpg
but from th_gen, it must be ../../amg/pic.jpg

that's just an idea, i'm not sure of it of course.

fluShaggy

Yes, i have tried a 2 variable method... it was using $series & &num

so for the line "../walls/amg/amg_01_800.jpg"

$series = amg
$num = 01

but i'm not sure how to combine this together in the image creating script.

I'm afraid I don't know the syntax quite well enough... hence my newbieness... but this is what I had it as.

$image = "../walls/".$series."/".$series."_".$num."_800.jpg"

And I again recieved nearly the same error. As for your comment refering to $_GET['image']... I have sadly never seen this nor do I know how to use it. ^{^;;} an example would be absoultely great.

I've also toyed with the directory problem, as I had no idea what else it could be... and that was not the case sadly. Again, thanks for the ideas!!!

jpmoriarty

anything that is appended to the URL as a variable (ie this.php?var=val) is a GET variable. You can have either POST variables that come from a form with the mentod POST, or you can have GET variables which will be appended to the URL.

If your globals are on, which most noobs like cos it's easier, then you can use the above example of a URL and simply type echo $var in the page, and it will print "val". however, this isnt good practice - it can lead to your variables popping up and being overwritten when that's not what you want. So most people will turn global variables off, and when you do that, the way to access your POST or GET variables is through $POST['variable name'] and $GET['variable name'].

So in this case you should try using $_GET['image'] and see if that solves anything.

On the two variables thing, i'd say (trying not to sound harsh) but you've split the string in the most ridiculous way. If you split it as i suggested (directory & file) then you can easily recombine them in your script, or do something like set the directory = $directory and then open $file or whatever. But to split the filename just seems a bit odd...

fluShaggy

well... THANK YOU!!!! We got it thanks to you!

jpmoriarty

ah! glad to hear it. 😃