basic help

JohnsonKJose

Hi All,

I am getting the following error while running the code

Error Message:

Notice: Undefined variable: name in g:\web\php\onlineshopproject\mailing-info\test\addrow.php on line 10
Name:
Notice: Undefined variable: email in g:\web\php\onlineshopproject\mailing-info\test\addrow.php on line 11
Email:
Notice: Undefined variable: secondaryemail in g:\web\php\onlineshopproject\mailing-info\test\addrow.php on line 12

Secondaryemail:

addRecord.html


<HTML>
<HEAD>
<TITLE> News Mail Registration Form </TITLE>
<META http-equiv="Content-Type" CONTENT="text/html; charset=iso-8859-1">
</HEAD>

<!-- Table-1 Starting -->
<TABLE bgcolor="#00FFFF" width="450" border="0" align="center" cellpadding="3">
<TR>
	<TD colspan="2">
		<div align="center"><FONT SIZE="6" COLOR="#FF0000">Entering Mailing List Information</FONT></div>
	</TD>
</TR>
<TR>
	<TD width="200">
		<div align="right"><B><FONT SIZE="" COLOR="#3300FF">Name</FONT></B></div>
	</TD>
	<TD width="250"><INPUT TYPE="text" NAME="name" size="35">
	</TD>
</TR>
<TR>
	<TD width="200">
		<div align="right"><B><FONT SIZE="" COLOR="#3300FF">e-mail</FONT></B></div>
	</TD>
	<TD width="250"><INPUT TYPE="text" NAME="email" size="35">
	</TD>
</TR>
<TR>
	<TD width="200">
		<div align="right"><B><FONT SIZE="" COLOR="#3300FF">Secondary e-mail</FONT></B></div>
	</TD>
	<TD width="250"><INPUT TYPE="text" NAME="secondaryemail" size="35">
	</TD>
</TR>
<TR>
	<TD colspan="2">
		<div align="center"><INPUT TYPE="submit" name="Submit" value="Submit"></div>
	</TD>
</TR>
</TABLE>
<!-- Table-1 Ending -->

</FORM>
</BODY>

</HTML>

addrow.php
<HTML>
<HEAD>
<TITLE> Add a new row in mail data table</TITLE>
</HEAD>

<?php
echo "Name: ".$name;
echo "Email: ".$email;
echo "Secondaryemail: ".$secondaryemail;
?>
</BODY>

</HTML>

Please help me where am I going wrong?

Thanks in advance
Regards
Johnson
🙁

barand

Replace

echo "Name: ".$name; 
echo "Email: ".$email; 
echo "Secondaryemail: ".$secondaryemail;

with

echo "Name: ".$_POST['name']; 
echo "Email: ".$_POST['email']; 
echo "Secondaryemail: ".$_POST['secondaryemail'];

JohnsonKJose

Hi Barand,
Thanks a lot, it is working.
actually my old code ($name) was working fine with php 4.0, then I have changed to php 4.3.1, after that my code started giving error.
can you please tell me how this $_POST['name'] is working?

Thanks in advance

Regards
Johnson
🙂

jassh

from what i understand,

$_POST['the_form's_object_name']

means, it return the value from the form's object.

mean, if you have a textbox named 'mytextbox', then
when you submit the form, having the $_POST['mytextbox']
you will have the value of the string you typed in the textfield previously..

hope that helps, if it does not confuse you first.. :p

example,

if you type in 'hello world' in a textbox named 'thetextbox'
then you submit it using $PHP_SELF
if you do this..

echo $_POST['thetextbox'];

it will return 'hello world'

try this for yourself.. 🙂


<?PHP
$from_textbox = $_POST['thetextbox'];

if(isset($_POST['submit'])) {
echo "You type <B>$from_textbox</B> in the textbox";
}

echo "<form name='form1' method='post' action='$PHP_SELF'>";
echo "<input type=text name=thetextbox size=25 maxlength=25>";
echo "<input type=submit name=submit value=Go!>";
echo "</form>";
echo "<BR>";


?>

-jassh

barand

Prior to 4.2 register_variables were on by default which meant that any GET or POST variables were immediately available by just using the variable name. However, it was realised that that this can be insecure so now they are off by default.

You now have to access them explicitly from $POST, $GET and $_COOKIE arrays.

keith73

Originally posted by JohnsonKJose
Hi Barand,
Thanks a lot, it is working.
actually my old code ($name) was working fine with php 4.0, then I have changed to php 4.3.1, after that my code started giving error.
can you please tell me how this $_POST['name'] is working?

Thanks in advance

Regards
Johnson
🙂

$POST is an associative array of all values passed to your script using the POST method. So if you submit a form, and its method is set to post, this array gets filled with all of the form's input.
If you send the form via the GET method or pass values to a script uisng a query string in the URL, the array $GET is filled with all values passed.
All cookies set by your server are read into $_COOKIE.

references:
http://www.php.net/manual/en/language.variables.predefined.php
http://www.php.net/manual/en/reserved.variables.php

These arrays are 'supergloabl' which means you can access the contents of the array anywhere in your scripts, including functions, without declaring them as global first. They are replacements for the now obsolete arrays, HTTP_POST_VARS, HTTP_GET_VARS, and HTTP_COOKIE_VARS.

Other useful arrays include $SERVER and $SESSION

examples of POST and GET

POST:
your form has 2 fields, name, email.
when the form is submitted, POST now has the names and values of these fields. $POST['name'] and $POST['email']

GET:
You pass 2 values to a script via the URL.
http://mydomain.ext/page2.php?foo=one&bar=seven
the GET now has these 2 name/value pairs, $GET['foo'] and $GET['bar']

Hope this sheds some light. Take a look at the manual pages for a lot of useful information.

Keith

phplearner

Originally posted by jassh
from what i understand,

try this for yourself.. 🙂


<?PHP
$from_textbox = $_POST['thetextbox'];

if(isset($_POST['submit'])) {
echo "You type <B>$from_textbox</B> in the textbox";
}

echo "<form name='form1' method='post' action='$PHP_SELF'>";
echo "<input type=text name=thetextbox size=25 maxlength=25>";
echo "<input type=submit name=submit value=Go!>";
echo "</form>";
echo "<BR>";


?>

-jassh [/B]

Umh, I just tried this and got:

Notice: Undefined index: thetextbox in c:\www\test\rmphp\textboxtest.php on line 2

Notice: Undefined variable: PHP_SELF in c:\www\test\rmphp\textboxtest.php on line 8

I am configured for 'register_globals off' ... just don't understand why this is a problem

barand

Its just telling you that the POST array does not contain a key called 'thetextbox.

The first time you access the script you have not submitted any values and so you get this message.

try


if(isset($_POST['submit'])) {
     $from_textbox = $_POST['thetextbox'];
     echo "You type <B>$from_textbox</B> in the textbox";
}

Alternatively you can set your error reporting level so that these notices are suppressed.

With $PHP_SELF -- if register_variables is off use $_SERVER[PHP_SELF]

hth

JohnsonKJose

Hi Barand, jassh, and Keith.
Thanks a lot for your help

Regards
Johnson
🙂