odd even number

[kenny873]

if I have a for loop :
for ($i=0; $i<count($replyDetails); $i++){
...
bgcolor = 123 (OR 456)...
...
}
and will show bgcolor = 123 if $i is an even number or $i=0
and will show bgcolor = 456 if $i is an odd number

how can i implement that?

[Weedpacket]

This is something you can use the mod operator (%) for.

if ($i%2==0)
{// $i is even
  $bgcolor = 123;
}
else
{// $i is odd
  $bgcolor = 456;
}

As the example shows, just set a variable for the background colour appropriately in each branch.

[Mordecai]

if ($i % 2 == 0) {
echo "123";
}
else {
echo "456";
}

The % is the mod operator, it just returns the remainder. The remainder of an even number divided by two is always equal to zero.

Hope this helps.