list of image file properties

dstonek

In my computer, from a certain folder/directory of jpge´s files I need to build a list of image file properties like path, size, width and height in pixels.
I´ve tried Extensis Portfolio but the "export to text file" is not friendly, I cannot keep the export preferences list.
Thanks in advance,
Daniel

Mordecai

First, open the directory you want to index:
$dir = opendir("C:/apache/htdocs");
Now, read the directory to get a file list:
while ($file = readdir($dir)) {
}
Inside this while, you'll need to get the image data:
$size = getimagesize($file);
$width = $size[0];
$height = $size[1];
Close the directory
closedir($dir);

So, with all of that said, you should have code similar to this:

$dir = opendir("C:/apache/htdocs");
while ($file = readdir($dir)) {
  $size = getimagesize($file);
  $width = $size[0];
  $height = $size[1];
  $path = "C:/apache/htdocs/".$file;
  echo($path."- ".$width.", ".$height); // or do whatever you want with the data
}
closedir($dir);

Hope this helps.

dstonek

Thanks for answering.
I am using PHP but I don´t know about scripting.
I don´t know why but I cannot create database connections to my localhost. (I am using DWMX), so I am working and testing on my remote server of my ISP.
I only need a simple way to get properties from large jpeg files in a text list. They are located in some Windows folders. They are the original files of which I have in my site at a smaller size. I want to add this info in the MySQL table.
Thanks for your code, I will work on it
Daniel

dstonek

Mordecai:

When I tryed with:

<?php $dir = opendir("C:/phpdev/www/ORIGINALES/dedos/originales/");
while ($file = readdir($dir)) {
$size = getimagesize($file);
$width = $size[0];
$height = $size[1];
$path = "C:/phpdev/www/ORIGINALES/dedos/originales/".$file;
echo($path."- ".$width.", ".$height); // or do whatever you want with the data
}
closedir($dir);?>

I got a long list of error messages (one per file) like this one:
Warning: getimagesize: Unable to open 'pedele6257.JPG' for reading. in c:\phpdev\www__originales\lista_originales.php on line 3
C:/phpdev/www/ORIGINALES__/dedos/originales/pedele6257.JPG- ,

JPEG files are Photoshop saved files. Is this a problem with getimagesize()? I am using php 4.2.3.
Thank you

dstonek

Mordecai:
Testing my localhost I found this simple code works fine

<?php
$file= "C:/phpdev/www/img/f1.jpg";
$size = getimagesize ($file);
echo "<img src= $file >" ;
echo $size[3]; ?>

In php.net I found the correct loop code is

while (false !== ($file = readdir($handle)))

instead of

while ($file = readdir($dir))

but your code isn´t still working: "unable to open for reading..."
Daniel

Mordecai

When I run it, it appears to be an error with opendir(). I don't know why, but it's only letting me pass relative directories. Do you get an opendir() error?

Also, I don't think my loop code should matter, but that one might be a little faster.

Well, since you're working with a file, that makes it a little easier.

Simply open the file for reading:
$file = fopen("file.name","rb"); // you can erase the "b" if you're on *nix

Then retrieve the data from the file:
$data = fread($file,filesize("file.name"));

Close your file:
fclose($file);

Now, you have a variable that contains all of the code, all on one line. We want to split that into multiple lines (an array, if you will) and loop through those:
$dataary = split("\n",$data);
for ($i=0;$i<count($dataary);$i++) {
// use image stuff from the last one here
// The filename is $dataary[$i]
}

dstonek

I´ve posted a similar question in another post and I´ve got an answer from jnuneznyc that solve that problem using a $path instead of the path itself and including $path.$file in getimagesize(). Anyway I will read carefully your last answer. Thank you for your help. Daniel