Form parsing -apprentice

anpanman

Hi,
I have the following form and display page.

<body>

</body>

<body>

<?php
if(empty($uname))
{
die("No Name submitted");
}
else
{
echo $uname;
}
?>

</body>

What I get is either 'No Name submitted' or 'Notice: Undefined variable: uname in d:....' when no IF statement. For now, all I want to do is display whatever from the form.

Please send this apprentice to the PHP world.

ir4z0r

replace all your variables $var passed by the form by $_POST['var']

kellog

On the second page where you want to display what was entered in the form, try using $_POST[uname] instead of $uname. i.e:

<?php
if(!$POST[uname])
{
die("No Name submitted");
}
else
{
echo $POST[uname];
}
?>

Originally posted by anpanman
Hi,
I have the following form and display page.

<body>

<form action="after.php" method="post" name="testform" id="testform" enctype="multipart/form-data">
<input type="text" name="uname" size="25" maxlength="25">
<input type="submit" name="submit" value="submit">
</form>

</body>

<body>

<?php
if(empty($uname))
{
die("No Name submitted");
}
else
{
echo $uname;
}
?>

</body>

What I get is either 'No Name submitted' or 'Notice: Undefined variable: uname in d:....' when no IF statement. For now, all I want to do is display whatever from the form.

Please send this apprentice to the PHP world.

BuzzLY

FYI, the reason this is happening is that register_globals is set to OFF in your PHP.INI file. That is a good thing -- it should be off. You should always use $_POST['var'] to refer to your variables, in case register_globals is turned off. This way, your code won't break.

I usually set all of the POST values into variables before I use them. This has the added benefit of then being able to refer to the variables directly instead of always using $_POST. Your code would simply require only one added line:

<?php 
// Here is your added line:
$uname = $_POST['uname'];

// Now your code should work:
if(empty($uname)) 
{ 
die("No Name submitted"); 
} 
else 
{ 
echo $uname; 
} 
?>