Problem for : Notice: Undefined variable

rikihw

Dear Sir,

I simplified the problem part for my php coding.
I got a
Notice: Undefined variable: tbxname
error message after I filled out a name and click ¡§submit¡¨ button.

It seems there is a problem for the ISAPI interface between my web server and client. (I am not sure).
Can anybody tell me how to solve this problem?
I use php4.3.1 version.
Thank you very much.

Here is the error part of my coding.

<form action="test.php" method=post name=form1>

    <p>Please input your name: <input name=tbxname></p>
    <input name=submit1 type=submit value=Submit>

</form>

The text you input is : <? echo $tbxname ?>

</body>
</html>

cgraz

you have globals set to off and error reporting to all. That means, you need to change

$tbxname to

$_POST['tbxname']

Cgraz

rikihw

Thanks Cgraz,

Another similar question,
I got the same error message in the following coding.
Do you know anything I need to change to
¡§echo¡¨ the ¡§new_name¡¨?
The MySql database is contact.list,
The database column has sn and new_name.

Thank you again.

<?
if ( $POST['tbxname'] )

{
$link_ID = mysql_connect("localhost","root
mysql_select_db("contact");

mysql_query("insert into list

(new_name)
values
('$POST[tbxname]')"
,$link_ID);

mysql_close($link_ID);

};

?>
<?
echo $new_name; // I got ¡§Notice: Undefined variable:
// new_name¡¨ error message here
?>

WindomEarle

at the beginning of your script add line

Error_reporting (E_PARSE);

Weedpacket

Better, instead of

if ( $_POST['tbxname'] )

use

if (!empty($_POST['tbxname'] ) )

. This will not only check that $_POST['tbxname'] has a nonzero value (as in the original test), but also that the variable is defined in the first place. (Better than asking PHP not to point out potential problems in your code.)

rikihw

It works.
Thank you very much.