problem with function definitions...

[nileshd]

I am trying to define a function which has default values for two of the arguments being passed to the function, but it does not want to accept variables as the default values. If I have static values, the defaults work fine, but as soon as I put variables, it breaks...

This is the version that works with static values

function executeQuery($query,$start=0,$limit=200)
{  ......  }

Thsi is the version with variables that is not working

function executeQuery($query,$start=$x,$limit=$y)
{   ...... }

Anyone knows how to make a function take variables as default values or if it is possible at all in php?

Thanks

[vallette]

I'm not positive but I doubt what you're trying to do is legal. PHP needs to know the default values before compiling the function code.

Why not do something like this:
executeQuery($query,$start,$x,$limit,$y)
{
if(!$start) $start=$x;
if(!$limit) $limit=$y
.
.
.
.
.
}

[WindomEarle]

yes, function some_f ($var = $x) is illegal in php. You may use only constants here.