eregi_replace

hyabusa

Hey, could someone please help me with a eregi_replace, i really am no good with them 🙁

I am trying to delete the following

<a href="%URL%" class="%ANYTHING%">More pages from %URL%</a>

The values of %URL% and %ANYTHING% are not known.

Thanks very much for any help.

Sxooter

Sure, I've been playing with them today in the garden, so they're still fresh in my memory.

If you're on a typical Linux box, by the way, try

man 7 regex

from the command line for a listing of how posix regex works.

Anyway, what you want is:

$s = 'Here is some text, with a link in it...';
$s.= '<a href="%URL%" class="%ANYTHING%">More pages from %URL%</a>';
$s.= 'And a little more after it.';
$s = eregi_replace('<a href.*</a>','',$s);
print $s;

Sxooter

Note that this is greedy, in that it will grab everything from the first a href to the last </a>...

If you need to process a whole file it would behoove you to just do it in a giant for next loop. Or use Perl Regexeps /s format of search and replace.