want to keep input from form while form is checking for errors...

[Hoangsta]

I have a form that ask for inputs. If users fill it out, and something is wrong or missing, after submitting, it will prompt with errors and display the form again already filled with the previous input if it was correct.

How do I do this?

My login.html form

<form action= "checkuser.php" method= "post" name= "login" id= "" >
<td width="188" valign="top"> <input name= "username" type= "text" id= "username" > </td>
<td valign="top"> <input name="password" type="password" id="password"> </td>
<td valign="top"> <input type="submit" name="submit" value="submit"> </td> </form>

checkuser.php page

<?
session_start();
$username= $POST ['username'];
$password = $POST['password']; if ((!$username) || (!$password)){
echo "Please enter ALL of the information! <br />";
include 'login_form.html'; exit(); }

any help is appreciated.

[sijis]

this is what i would do.

form.php

<form action= "checkuser.php" method= "post" name= "login" id= "" >
<td width="188" valign="top"> <input name= "username" type= "text" id= "username" value="<?php echo $REQUEST['u']; ?>"> </td>
<td valign="top"> <input name="password" type="password" id="password" value="<?php echo $REQUEST['p']; ?>"> </td>
<td valign="top"> <input type="submit" name="submit" value="submit"> </td> </form>

checkuser.php

foreach ($_POST as $key => $value) {
	if($_POST[$key] == ""){
		$url = "?u=".urlencode($_POST['username']);
		$url .= "&p=".urlencode($_POST['password']);

	header("Location: [url]http://[/url]$_SERVER[HTTP_HOST]/form.php$url");
}

the foreach makes sure that all the fields are filled out, if they aren't, the user is redirected back to the form.php page with anything else filled out. otherwise, if all the fields ARE filled out, the code continues.

hope that helps.