Switching between Thumbnail and Large version

cosmo7

3 photos...
How do I go about coding a page where there is 1 large photo and the remaining 2 photos are thumbnails on the side...
The photo that will be the enlarged photo will be determined by a variable and no matter what, the remaing 2 will be thumbnails...
For example if the page is (page.php)
then the picture variable is say picture1 (page.php?picture=picture1)
then picture number 1 will be the enlarged photo (2 and 3 are the thumbnails)
Clicking on one of the thumbnails will reload the page with IT as the enlarged photo...
I've given a picture example of what I want...
(I already HAVE 2 versions of each photo already made. Large version and thumbnail version)

khaine

You need to use a switch based on the incoming picture variable something like

<HTML>
<HEAD>
<TITLE></TITLE>
</HEAD>

<BODY>

<?php

switch($picture)
{
    default :
    case 1  : echo "<IMG border=0 src=\"picture1.jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"picture2.jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"picture3.jpg\"></A>";
              break;
    case 2  : echo "<IMG border=0 src=\"picture2.jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"picture1.jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"picture3.jpg\"></A>";
              break;
    case 3  : echo "<IMG border=0 src=\"picture3.jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"picture2.jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"picture1.jpg\"></A>";
              break;
}
?>

</BODY>
</HTML>

how's that?

Mark.

cosmo7

I tried your script and it worked BUT...
the first time it shows I need the $picture variable to be used as a filename that I pull out of a mySQL data table... something like $picture.jpg I'm just having problems with the quotation marks and stuff... Take alook at the following script and show me how to do it appropriatly so that instead of picture1.jpg I want something like ($picture).jpg and so on and so forth. ALSO, I'm having problems with the PATH. My pictures are in a directory called "pics" and the thumbnails are in "pics/thumbs" how do I write it without messing up?

<?php
include("dbinfo.inc.php");


$db = mysql_connect("$database", "$username", "$password");



mysql_select_db("database",$db);



$result = mysql_query("SELECT * FROM items WHERE pic1='$picture'",$db);
$num = mysql_numrows($result);
?>



<?
$i=0;
while ($i < $num) {

$picture=mysql_result($result,$i,"pic1");
$picture2=mysql_result($result,$i,"pic2");
$picture3=mysql_result($result,$i,"pic3");


switch($picture)
{
    default :
    case 1  : echo "<IMG border=0 src=\"picture1.jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"picture2.jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"picture3.jpg\"></A>";
              break;
    case 2  : echo "<IMG border=0 src=\"picture2.jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"picture1.jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"picture3.jpg\"></A>";
              break;
    case 3  : echo "<IMG border=0 src=\"picture3.jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"picture2.jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"picture1.jpg\"></A>";
              break;
}
?>

khaine

<?php
include("dbinfo.inc.php");

$db = mysql_connect("$database", "$username", "$password");

mysql_select_db("database",$db);

$result = mysql_query("SELECT * FROM items WHERE pic1='$picture'",$db);
$num = mysql_numrows($result);
?>

<?
$i=0;
while ($i < $num) {

$picture1=mysql_result($result,$i,"pic1");
$picture2=mysql_result($result,$i,"pic2");
$picture3=mysql_result($result,$i,"pic3");


switch($picture)
{
    default :
    case 1  : echo "<IMG border=0 src=\"pics\".$picture1.".jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"pics\thumbs\".$picture2.".jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"pics\thumbs\".$picture3.".jpg\"></A>";
              break;
    case 2  : echo "<IMG border=0 src=\"pics/".$picture2.".jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"pics\thumbs\".$picture1.".jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"pics\thumbs\".$picture3.".jpg\"></A>";
              break;
    case 3  : echo "<IMG border=0 src=\"pics\".$picture3.".jpg\">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"pics\thumbs\".$picture2.".jpg\"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"pics\thumbs\".$picture1.".jpg\"></A>";
              break;
}
?>

that should do it

Mark.

cosmo7

It doesn't work
it reports a parcing error...

khaine

where is the parsing error? does it give a line number? or any more details

cosmo7

It reports a parce problem on LINE 31 but I couldn't see the problem... maybe you should check the script?

run_GMoney

The error is right here:

case 2  : echo "<IMG border=0 src=\"pics/".$picture2.".jpg\">";

change the "/" to a "\" and try again.

cosmo7

That doesn't work either

run_GMoney

Ok, if you want some help, you're gonna need to be a little more specific than "That doesn't work either." Did you get the same error? A different error? Be as specific as you possibly can. Remember we're not seeing everything you see.

cosmo7

It gives me the same parcing error...
on LINE 31.

run_GMoney

Take out the last "\" after .jpg The new line should look just like this:

case 2  : echo "<IMG border=0 src=\"pics\".$picture2.".jpg">";

cosmo7

I still get the same message:

Parse error: parse error, expecting ','' or';'' in /usr/local/plesk/apache/vhosts/myhost/switchpics.php on line 31

run_GMoney

Throw your code up here real fast. Let's see what you got. Something may have been erased that shouldn't have amongst all that.

cosmo7

<?php
include("dbinfo.inc.php");

$db = mysql_connect("$database", "$username", "$password");

mysql_select_db("mydatabase",$db);

$result = mysql_query("SELECT * FROM items WHERE pic1='$picture'",$db);
$num = mysql_numrows($result);
?>

<?
$i=0;
while ($i < $num) {

$picture1=mysql_result($result,$i,"pic1");
$picture2=mysql_result($result,$i,"pic2");
$picture3=mysql_result($result,$i,"pic3");


switch($picture)
{
    default :
    case 1  : echo "<IMG border=0 src=\"pics\".$picture1.".jpg">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"pics\thumbs\".$picture2.".jpg"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"pics\thumbs\".$picture3.".jpg"></A>";
              break;
    case 2  : echo "<IMG border=0 src=\"pics\".$picture2.".jpg">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"pics\thumbs\".$picture1.".jpg"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=3\"><IMG border=0 src=\"pics\thumbs\".$picture3.".jpg"></A>";
              break;
    case 3  : echo "<IMG border=0 src=\"pics\".$picture3.".jpg">";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=2\"><IMG border=0 src=\"pics\thumbs\".$picture2.".jpg"></A>";
              echo "&nbsp;";
              echo "<A href=\"switchpics.php?picture=1\"><IMG border=0 src=\"pics\thumbs\".$picture1.".jpg"></A>";
              break;
}
?>

Here you go doctor... can you fix it?

run_GMoney

Let's try to get something without all the escape characters. Let's try this and see what you get. I'm not even sure if this will work but we can try.

<?php
include("dbinfo.inc.php");

$db = mysql_connect("$database", "$username", "$password");

mysql_select_db("database",$db);

$result = mysql_query("SELECT * FROM items WHERE pic1='$picture'",$db);
$num = mysql_numrows($result);
?>

<?
$i=0;
while ($i < $num) {

$picture1=mysql_result($result,$i,"pic1");
$picture2=mysql_result($result,$i,"pic2");
$picture3=mysql_result($result,$i,"pic3");


switch($picture)
{
    default :
    case 1  : echo "<IMG border=0 src=/pics/" . $picture1 . ".jpg>";
              echo "&nbsp;";
              echo "<A href=switchpics.php?picture=2><IMG border=0 src=/pics/thumbs/" . $picture2 . ".jpg></A>";
              echo "&nbsp;";
              echo "<A href=switchpics.php?picture=3><IMG border=0 src=/pics/thumbs/" . $picture3 . ".jpg></A>";
              break;
    case 2  : echo "<IMG border=0 src=/pics/" . $picture2 . ".jpg>";
              echo "&nbsp;";
              echo "<A href=switchpics.php?picture=2><IMG border=0 src=/pics/thumbs/" . $picture1 . ".jpg></A>";
              echo "&nbsp;";
              echo "<A href=switchpics.php?picture=3><IMG border=0 src=/pics/thumbs/" . $picture3 . ".jpg></A>";
              break;
    case 3  : echo "<IMG border=0 src=/pics/" . $picture3 . ".jpg>";
              echo "&nbsp;";
              echo "<A href=switchpics.php?picture=2><IMG border=0 src=/pics/thumbs/" . $picture2 . ".jpg></A>";
              echo "&nbsp;";
              echo "<A href=switchpics.php?picture=1><IMG border=0 src=/pics/thumbs/" . $picture1 . ".jpg></A>";
              break;
}
?>

cosmo7

That didn't work. This time I get the following error:

Parse error: parse error in /usr/local/plesk/apache/vhosts/myhost/switchpics.php on line 57

run_GMoney

There's only about 46 or 47 lines in that entire code. Is there something else in the code you're using?

cosmo7

No I'm not using any more php on that switchpics.php script
Maybe it's a problem with the WHILE loop "{"
I'd change it but it would interfere with the SWITCH thing?

run_GMoney

You know, that while loop isn't closed. Change it to this:

while ($i < $num) 
{
$picture1=mysql_result($result,$i,"pic1");
$picture2=mysql_result($result,$i,"pic2");
$picture3=mysql_result($result,$i,"pic3");
}

and see what happens.....slowly but surely....

WAIT!!!! Don't do that. Just add another "}" after the very last one at the bottom. Sorry bout that. I hadn't looked at what that loop was actually doing.