Sorting issues and going about things wrong

piecz

I know I am going about this the wrong way. Maybe someone can shed some light on this.

My project is reading info from an ldap server and then dynamically building pages. This much is working perfect!

I now want to build another html file for the index and am having a few problems. From my newbie book I found a way to create a bullet list from the directory. The problem is I need it sorted by file name.

Maybe the short answer here is learning to remote sort a directory prior to making the bullet list.

Unable to do this I did the following:

during my iteration with the ldap server I created an array of filenames. I then sorted this array using

sort(file_list);

I did a for loop with an echo and everything looks great. The problem is in building the page I have created a $index_file variable to hold all the html and while I can return individual values from the array without issue as $file_list[4]) , I cannot call my for loop and have it execute as code. It only resolves the variables and gives a text representation of the code.

Here is the code snippet:

$index_output = "
<HTML>
<HEAD>
<TITLE> $index_title </TITLE>
</HEAD>

<BODY>
for ($i=0;$i<$nelements;$i++) {
echo $file_list[$i];
}

<P>test</P>
</BODY>
</HTML>
";

and the output in index.html:

for (12=0;12<12;12++) { echo ; }
test

So is what I am doing completely stupid and should I just find a way to sort the remote directory by filename and then build my list?

Or can this code be made to work. I have spent a few hours playing with trying to create dynamic variables and assign data to the array from them then building a huge concatenation from these values and calling it in the html output, but I think I am going off the deep end here and need help from others.

Thanks,

Tony

YappyDog

I think what you want to use is the asort function. From the manual:

asort -- Sort an array and maintain index association

http://www.php.net/manual/en/function.asort.php

Their example:

$fruits = array ("d"=>"lemon", "a"=>"orange", "b"=>"banana", "c"=>"apple");
asort ($fruits);
reset ($fruits);
while (list ($key, $val) = each ($fruits)) {
echo "$key = $val\n";
}

eternalprophet

$index_output = "
<HTML>
<HEAD>
<TITLE> $index_title </TITLE>
</HEAD>

<BODY>
<?
for ($i=0;$i<$nelements;$i++) {
echo $file_list[$i];
}
?>
<P>test</P>
</BODY>
</HTML>
";

Untested. If you have a php statement, it needs to be enclosed some way in <? script here ?> from my understanding.

piecz

Thanks for the response.

If I use the <? ?> tags it does not generate anything in my output file.

As far as using asort I have no problem sorting the array with the sort command and can echo out the information just fine. I just cannot insert that code in my output variable for writing the file.

This is really driving me nuts...

I guess there is no way to just do a directory sort on the remote server as I have been googling for a couple hours now.

Any suggestions on how to get this list embedded properly in my output file would be a big help.

tijger

hey Tony,

try this:

$index_output = "
	<HTML>
	<HEAD>
	<TITLE> $index_title </TITLE>
	</HEAD>

<BODY>";

for ($i=0;$i<$nelements;$i++) {
    $index_output .= $file_list[$i];
}

$index_output .= "<P>test</P>
	</BODY>
	</HTML>
	";

good luck!
greetings, tijger

piecz

tijger -

You are awesome!

Thanks so much.....

Tony