retain radio button

kir441

I created 4 radio buttons in a form.

<form method="post" action="dwdictionary.php" name="testForm">
<font face="Verdana" size="1">
<input type="radio" name="SearchType" value="DWTable"> Data Warehouse table name<br>
<input type="radio" name="SearchType" value="DWField"> Data Warehouse field name<br>
<input type="text" name="T1" value ="" size="27"><br><br>
<input type="submit" value="Search" name="B1" onclick="javascript:getValue();">
 <input type="reset" value="Reset" name="B2">
<hr size="4" noshade color="#003399">
</form><br>

What should I do in order to retain the checked radio button in next form?
I know that I have to write a javascript function but I tried but could not write it.

Thanks
Kiran

leatherback

Have a look at this thread:

http://www.phpbuilder.com/board/showthread.php?threadid=10238157

kir441

Leatherback

thanks for the reply, but can you make it clear, because global variables are not working in my php page. Can you tell the exact java script function.

Thanks!

drawmack

<?php
  $stChecked = array('','');
  if ($B1 == 'Search') {
     switch ($SearchType) {
        case 'DWTable':
          $stChecked[0] = 'checked';
           break;
        case 'DWField':
          $stChecked[1] = 'checked';
           break;
     } //end switch
  } //end if
?>

<form method="post" action="dwdictionary.php" name="testForm">
<font face="Verdana" size="1">
<input type="radio" name="SearchType" value="DWTable" <?=$stChecked[0]?>> Data Warehouse table name<br>
<input type="radio" name="SearchType" value="DWField" <?=$stChecked[1]?>> Data Warehouse field name<br>
<input type="text" name="T1" value ="" size="27"><br><br>
<input type="submit" value="Search" name="B1" onclick="javascript:getValue();">
 <input type="reset" value="Reset" name="B2">
<hr size="4" noshade color="#003399">
</form><br>

that should do the trick

kir441

Thanks Drawmack

Still it did not work. Can anyone give me another solution.

Thanks

leatherback

Hi,

One more try:


 switch($_POST['SearchType'])
   {
    case "DWTable":
    ST0 = "checked";
    break;

case "DWField":
ST1 = "checked";
break;
   }


<form method="post" action="dwdictionary.php" name="testForm"> 


<input type="radio" <? echo ST0; ?> name="SearchType" value="DWTable"> Data Warehouse table name<br> 
<input type="radio" <? echo ST1; ?> name="SearchType" value="DWField"> Data Warehouse field name<br> 


<input type="text" name="T1" value ="" size="27"><br><br> 
<input type="submit" value="Search" name="B1" onclick="javascript:getValue();"> 
 <input type="reset" value="Reset" name="B2"> 
<hr size="4" noshade color="#003399"> 
</form><br>

Suppose this should work.

kir441

Any more suggestions.

leatherback

Hi Kir,

Eerhh..

WHAT is it that doesn't work? Are the variables passed to the next page?
Is there a $_POST array? or perhaps you should use $HTTP_POST_VALUE?

I see you call a javascript when you subit the form. Does this perhaps give you the headache?

Please, some more info on where the problem is, because the solutions given should work (I use them myself on my site for a dropdown menu, no problem).

Sxooter

First off, you don't need javascript to do this.

Let's say we're posting the form on page 1 to the form on page 2. We'll have a var something like this:

$_POST['SearchType']

that is a radio button, that can be, let's say, yes,no or maybe. When we build the new buttons, we need to test it, something like this:

<?php
$choices = array("yes","no","maybe");
foreach($choices as $choice){
  print '<input type="radio" name="SearchType" value="'.$choice.'"';
  if ($POST['SearchType']==$choice) print ' checked';
  print '>';
}
?>

You need to do that for each of your radio buttons. This lets you do the work in PHP and NOT create another layer of javascript, and will work with non-js enabled browsers (if you write code for gov't offices and such, you never know what they're NOT gonna have this week.)