Detection of a subdirectory possible???!!!

roy_ENHOST

Hi guys

Im trying to get PHP to detect a subdirectory.
If the subdirectory exist, I want it to insert the HTML tag <a href="/images">images</a> into the page.
If the subdirectory doesnt exist, nothing will be inserted in the page.

Is this even possible?

shamly

Yes it is possible.
use the opendir function to get the directory handle
next, within a while loop you can browse through the directory & see if there are any directories by using the is_dir function.

eg.

  $handle = opendir(path);

  while($filename = readdir($handle))
  {
       if ($filename != "." && $filename != "..")
      {
if(is_dir($filename))
                echo "This is a directory";
      }
  }

try it out

roy_ENHOST

Hi Shamly,

Your codes works like a charm.
There is only one glitch though.
When there is no specific directory PHP prints out the ugly error codes:
"Warning: opendir(images) [function.opendir]: failed to open dir: No such file or directory in /home/enhost/public_html/dir.php on line 2

Warning: readdir(): supplied argument is not a valid Directory resource in /home/alphaill/public_html/dir.php on line 4"

I wanted it to printout nothing if there is no such directory.

Originally posted by shamly
Yes it is possible.
use the opendir function to get the directory handle
next, within a while loop you can browse through the directory & see if there are any directories by using the is_dir function.

eg.
  $handle = opendir(path);

  while($filename = readdir($handle))
  {
       if ($filename != "." && $filename != "..")
      {
if(is_dir($filename))
                echo "This is a directory";
      }
  }
try it out [/B]

roy_ENHOST

Oh sorry.

I forgot there is an error suppression '@' in PHP. 🙂
Sorry I just woke up, my brains still kinda asleep thats why.

Thank you so much,shamly!
Gonna get a cup of hot coffee now.

shamly

B4 the line

$handle = opendir(path);

you can check if "path" is a directory using the is_dir function. then you if it is then continue.

roy_ENHOST

I don't get it.

The script is misbehaving a little.

Here is the exact script I use:

<?
$handle = opendir(photos);

while($filename = readdir($handle))
{
if ($filename != "." && $filename != "..")
{
if(is_dir($filename))
print '<font color="#0033CC">There is a photo folder</font>';
}
}
?>

The script works for relative path but how do we make it detect absolute path like : http://www.something.com/dir/ ?

shamly

I dont think you can access a web dir as a full path.
Only dirctories (eg. "C:\Temp") can be opened as a full path using the "opendir" function.

as for the error that pops out when no directory has been specified first check if the path specified is a directory, and if it is, then use the opendir function like what i have done below

if (is_dir(photos))
{
$handle = opendir(photos);

while($filename = readdir($handle))
{
if ($filename != "." && $filename != "..")
{
if(is_dir($filename))
print '<font color="#0033CC">There is a photo folder</font>';
}
}
}
?>